Chapter 9.4, Problem 10E

To determine

To find: The terminal point Q.

Answer to Problem 10E

The terminal point Q is $\left(17,-1,14\right)$ .

Explanation of Solution

Given information:

The pointand vector is $P\left(-6,4,2\right),v\langle 23,-5,12\rangle$ .

Calculation:

The vector $v$ is,

$v=\langle x_2-x_1,y_2-y_1,z_2-z_1\rangle$

Substitute the values in above equation.

$\begin{array}{c}\langle 23,-5,12\rangle =\langle x-\left(-6\right),y-4,z-2\rangle \\ \langle 23,-5,12\rangle =\langle x+6,y-4,z-2\rangle \end{array}$

Compare left and right side of above equation.

$\begin{array}{l}x+6=23\\ x=17\\ y-4=-5\\ y=-1\\ z-2=12\\ z=14\end{array}$

Thus, the terminal point Q is $\left(17,-1,14\right)$ .