Chapter 9.3, Problem 35P

Solve each equation by finding square roots. If the equation has no real-number solution, write no solution. If a solution is irrational, round to the nearest tenth. $11x^2-0.75=3.21$

To determine

To Find:

The number of solutions of the given equation.

Answer to Problem 35P

The given equation has two solutions $x=0.6,x=-0.6$ .

Explanation of Solution

Given information:

The given equation is $11x^2-0.75=3.21$ .

Consider the given equation $11x^2-0.75=3.21$ .

  $11x^2-0.75=3.21$

Add $5$ from both sides.

  $\begin{array}{l}11x^2-0.75+0.75=3.21+0.75\\ 11x^2=3.96\\ \frac{11x^2}{11}=\frac{3.96}{11}\\ x^2=0.36\\ x=\pm 0.6\\ x=0.6,x=-0.6\end{array}$

Therefore, the given equation has two solutions $x=0.6,x=-0.6$ .