The reaction through which, the given substrate more likely to participate has to be identified. Concept Introduction: The compound that is been attacked by nucleophile is known as electrophile. Usually electrophile is referred as substrates. Valency of carbon atom is four. Therefore, carbon atom has four bonds. Hence, apart from the bond that is with the leaving group, the carbon atom contains three other bonds also. Out of the three bonds that are present apart from the leaving group, if one is an alkyl group, then the substrate is known as “primary”. If there are two alkyl groups, then the substrate is known as “secondary”. If there are three alkyl groups, then the substrate is known as “tertiary”. This is represented as shown below, In S N 2 reaction, the alkyl groups are more crowded. Hence, the nucleophile cannot attack the electrophilic center easily if there are three alkyl groups. Therefore, for S N 2 reaction, the primary substrate is more susceptible for nucleophilic attack, while the tertiary substrate is unreactive. In S N 1 reaction, the first step is the loss of leaving group to form a carbocation. The second step is the attack of nucleophile on carbocation. In this case, the stability of the carbocation formed is the major issue. As we know that the alkyl groups are electron donating groups, the more the alkyl groups substituted, the more the carbocation formed will be stabilized. Hence, tertiary is more stable than the secondary, and the primary is the worst as it contains only one alkyl group. In simple words, we can say that, if the substrate is a primary or secondary one, then the reaction will proceed through S N 2 mechanism. The final product has inversion of configuration. If the substrate is tertiary means, then the reaction will proceed through S N 1 mechanism and the final product is racemic.

Question

ii) Molecular ion peak :the peak corresponding to the intact molecule (with a positive charge) What would the base peak and Molecular ion peaks when isobutane is subjected to Mass spectrometry? Draw the structures and write the molecular weights of the fragments. Circle most stable cation a) tert-butyl cation b) Isopropyl cation c) Ethyl cation. d) Methyl cation 6. What does a loss of 15 represent in Mass spectrum? a fragment of the molecule with a mass of 15 atomic mass units has been lost during the ionization Process 7. Write the isotopes and their % abundance of isotopes of i) Cl

Answer 1

Question

Chapter 9.2, Problem 9.3P

Interpretation Introduction

Interpretation:

The reaction through which, the given substrate more likely to participate has to be identified.

Concept Introduction:

The compound that is been attacked by nucleophile is known as electrophile. Usually electrophile is referred as substrates. Valency of carbon atom is four. Therefore, carbon atom has four bonds. Hence, apart from the bond that is with the leaving group, the carbon atom contains three other bonds also.

Out of the three bonds that are present apart from the leaving group, if one is an alkyl group, then the substrate is known as “primary”. If there are two alkyl groups, then the substrate is known as “secondary”. If there are three alkyl groups, then the substrate is known as “tertiary”. This is represented as shown below,

In SN2 reaction, the alkyl groups are more crowded. Hence, the nucleophile cannot attack the electrophilic center easily if there are three alkyl groups. Therefore, for SN2 reaction, the primary substrate is more susceptible for nucleophilic attack, while the tertiary substrate is unreactive.

In SN1 reaction, the first step is the loss of leaving group to form a carbocation. The second step is the attack of nucleophile on carbocation. In this case, the stability of the carbocation formed is the major issue. As we know that the alkyl groups are electron donating groups, the more the alkyl groups substituted, the more the carbocation formed will be stabilized. Hence, tertiary is more stable than the secondary, and the primary is the worst as it contains only one alkyl group.

In simple words, we can say that, if the substrate is a primary or secondary one, then the reaction will proceed through SN2 mechanism. The final product has inversion of configuration. If the substrate is tertiary means, then the reaction will proceed through SN1 mechanism and the final product is racemic.

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