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(a)
Interpretation:
The major product of the given reaction has to be given.
Concept introduction:
In the nucleophilic substitution reaction, the
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergo
(b)
Interpretation:
The major product of the given reaction has to be given.
Concept introduction:
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
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Chapter 9 Solutions
Essential Organic Chemistry Study Guide & Solution Manual, Books a la Carte Edition
- Please correct answer and don't use hand ratingarrow_forwardNonearrow_forwardQ1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI Br : Н OH H wo་ཡིག་ཐrow HO 3 D ။။ဂ CI Br H, CI Br Br H₂N OMe R IN I I N S H Br ជ័យ CI CI D OHarrow_forward
- Please correct answer and don't use hand ratingarrow_forwardNonearrow_forward%Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forward
- Nonearrow_forwardCH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forwardDraw the correct ionic form(s) of arginine at the pKa and PI in your titration curve. Use your titration curve to help you determine which form(s) to draw out.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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