a. Explanation Given: The function f ( x ) = e − x and x = − 0.2 , − 0.1 , 0.0 , 0.1 , and 0.2 . The Taylor polynomials, p 1 ( x ) = 1 − x . and p 2 ( x ) = 1 − x + x 2 2 . Calculation: Use the online calculator and obtain the absolute error. The value of | e − x − p 1 ( x ) | is shown in below Table. x p 1 ( x ) = 1 − x e − x | e − x − p 1 ( x ) | −0.2 1 − ( − 0.2 ) = 1.2 1.221402758 2.14 × 10 − 2 −0.1 1 − ( − 0.1 ) = 1.1 1.105170918 5.17 × 10 − 3 0.0 1 − 0 = 1 1 0 0.1 1 − ( 0.1 ) = 0.9 0.9048374180 4.84 × 10 − 3 0.2 1 − ( 0.2 ) = 0.8 0.8187307530 1.87 × 10 − 2 The value of | e − x − p 2 ( x ) | is shown in below Table. x p 2 ( x ) = 1 − x + x 2 2 e − x | e − x − p 2 ( x ) | −0.2 1 − ( − 0.2 ) + ( − 0 b. To determine To describe: The error varying with x in each column and find the values of x largest and smallest in magnitude.

Calculus: Early Transcendentals (2nd Edition)

2nd Edition

ISBN: 9780321947345

Author: William L. Briggs, Lyle Cochran, Bernard Gillett

Publisher: PEARSON

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Chapter 9.1, Problem 87E

To determine

To approximate: The absolute error to significant digits at the given points.

To determine

To describe: The error varying with x in each column and find the values of x largest and smallest in magnitude.

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Chapter 9.1, Problem 86E

Chapter 9.1, Problem 88E

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Chapter 9 Solutions

Calculus: Early Transcendentals (2nd Edition)

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To approximate: The absolute error to significant digits at the given points.

Solution Summary: The author explains how to approximate the absolute error to significant digits at the given points.

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To approximate: The absolute error to significant digits at the given points.

To describe: The error varying with x in each column and find the values of x largest and smallest in magnitude.

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Chapter 9 Solutions