A stepwise synthesis of propranolol from the given starting materials is to be stated. Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile ( − OR ) . The nucleophilic attack of − NH 2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of − OR on the less substituted carbon of epoxide follow S N 2 pathway.

Question

Want to see the full answer?

Answer 1

Question

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Calculate the chemical shifts in 13C and 1H NMR for 4-chloropropiophenone ? Write structure and label hydrogens and carbons

Please sirrr soollveee these parts pleaseeee and thank youuuuu

Please sirrr soollveee these parts pleaseeee and thank youuuuu, don't solve it by AI plleeaasseee

Answer 2

Question

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Answer 6

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Answer 7

Chapter 9, Problem 9.73P

Interpretation Introduction

Interpretation: A stepwise synthesis of propranolol from the given starting materials is to be stated.

Concept introduction: Alcohols react with NaH and form alkoxide salts. An alkoxide salt contains strong nucleophile (−OR). The nucleophilic attack of −NH2 on the electron deficient carbon atom of epichlorohydrin and the nucleophilic attack of −OR on the less substituted carbon of epoxide follow SN2 pathway.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Solution Summary: The author explains how alcohols react with NaH and form alkoxide salts. The nucleophilic attack on the electron deficient carbon atom of epichlorohydrin

Concept explainers

Want to see the full answer?