(a) Interpretation: The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated. 2 CH 3 OH ( l ) + O 2 → 2 HCHO ( g ) + 2H 2 O ( l ) : Δ H r ° = − 326. 2 kJ And standard heat of combustion of hydrogen is given by the equation: H 2 ( g ) + 1 2 O 2 → H 2 O ( l ) : Δ H ^ e ° = − 285. 8 kJ Concept introduction: The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy. In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

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Answer 1

Question

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

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In the production of ethyl acetate via reactive distillation, the column operates at 5 bar with an equimolar feed (ethanol + acetic acid) at 80°C. The reaction follows: \[CH_3COOH + C_2H_5OH \rightleftharpoons CH_3COOC_2H_5 + H_2O \quad (K_{eq} = 4.2 \text{ at } 80°C)\] Given: - NRTL parameters for all binary pairs - Tray efficiency = 65% - Vapor-liquid equilibrium exhibits positive azeotrope formation Calculate the exact minimum reflux ratio required to achieve 98% ethyl acetate purity in the distillate, assuming: 1) The reaction reaches equilibrium on each tray 2) The heavy key component is water

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Answer 2

Question

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

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Answer 3

Question

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

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Answer 4

Question

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

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Answer 5

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

Answer 6

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Answer 7

Chapter 9, Problem 9.6P

Interpretation Introduction

(a)

Interpretation:

The standard heat of the formaldehyde formation from methanol and oxygen reaction given by the equation should be calculated.

2CH3OH(l)+O2→2HCHO(g)+2H2O(l):ΔHr°=−326.2 kJ

And standard heat of combustion of hydrogen is given by the equation:

H2(g)+12O2→H2O(l):ΔH^e°=−285.8 kJ

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The need of following the Hess’s Law to find the standards of reaction the given equation in sub part (a) should be explained.

Concept introduction:

The standard heat of combustion is the number of calories or the total energy generated as heat when a certain compound goes through combustion in presence of oxygen under the standard conditions. Generally, a hydrocarbon reacts with oxygen in this type of reaction. This is also an exothermic reaction as it generates heat energy.

In Hess’s law, enthalpy change which involved in the chemical reactions are same, it doesn’t matter the steps involved in the reactions. This reaction seems to be an endothermic reaction.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 9 - The standard heat of the reaction...Ch. 9 - Prob. 9.2P Ch. 9 - Prob. 9.3P Ch. 9 - The standard heat of the reaction...Ch. 9 - Prob. 9.5P Ch. 9 - Prob. 9.6P Ch. 9 - Prob. 9.7P Ch. 9 - Prob. 9.8P Ch. 9 - The standard heat of combustion of gaseous ethane...Ch. 9 - The standard heat of combustion (AH°) of liquid...

Solution Summary: The author explains that the standard heat of the formaldehyde formation from methanol and oxygen reaction should be calculated.

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