Chapter 9, Problem 9.57SP

Interpretation Introduction

Interpretation:

PVwork done and change in internal energy should be determined.

Concept introduction:

Increase in the internal energy is the amount of total heat added to the work done on the system by its surroundings.
And
Let w is the work done and $\text{P}$ is the pressure and $\text{dV}$ is the change in the volume

  $\partial \text{w}=-\text{PdV}$

Pressure is constant, thus integrating the above equation:
$\text{w}=-\text{PdV}$

Given:

  ${\text{2H}}_{\text{2}}\text{(g)}{\text{+O}}_{\text{2}}\to {\text{2H}}_{\text{2}}\text{O(g) ΔH°}=-\text{484 kJ}$

Moles of ${\text{H}}_{\text{2}}$ = $0.50$

Moles of ${\text{O}}_{\text{2}}$ = $0.25$

Volume change= $-5.6\text{ L}$