Explanation Here, the combustion energy of glucose can be expressed by following method: Under a calorimeter, Heat gain = Heat loss Hence, the combustion energy will be equal to heat gained by system so as: H e a t gain by water + heat gain by calorimeter = C o m b u s t i o n heat of glucose Now, heat gain by water: Q = c × m × Δ T Putting the values we get: Q = 4.18 J / g . 0 C × 250 g × 18.6 0 C = 19437 J = 19.437 k J Heat gain by calorimeter: q v = C × Δ T Putting the values we get: q v = 623 J / 0 C × 18.6 0 C = 11587.8 J = 11.5878 k J ≃ 11

Chemistry, Books a la Carte Edition and Modified Mastering Chemistry with Pearson eText & ValuePack Access Card (7th Edition)

7th Edition

ISBN: 9780134172514

Author: John E. McMurry

Publisher: PEARSON

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Chapter 9, Problem 9.12A

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Change in combustion energy ΔE of glucose in calorimeter in kJ/g and cal/g.

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Chapter 9, Problem 9.11P

Chapter 9, Problem 9.13P

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Chemistry, Books a la Carte Edition and Modified Mastering Chemistry with Pearson eText & ValuePack Access Card (7th Edition)

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Change in combustion energy Δ E of glucose in calorimeter in kJ/g and cal/g.

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To determine:

Change in combustion energy ΔE of glucose in calorimeter in kJ/g and cal/g.