Modern Database Management
13th Edition
ISBN: 9780134773650
Author: Hoffer
Publisher: PEARSON
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Chapter 9, Problem 9.39PAE
You are to construct a star schema for Simplified Automobile Insurance Company (for a more realistic example, Kimball, 1996b). The relevant dimensions, dimension attributes, and dimension sizes are as follows:
| InsuredParty |
Attributes: InsuredPartylD and Name. There is an average of two insured parties for each policy and covered item. |
| Coverageltem |
Attributes: CoverageKey and Description. There is an average of 10 covered items per policy |
| Agent |
Attributes: AgentID and AgentName. There is one agent for each policy and covered item. |
| Policy |
Attributes: PolicylD and Type. The company has approximately 1 million policies at the present time. |
| Period |
Attributes: DateKey and FiscalPeriod. |
Facts to be recorded for each combination of these dimensions are PolicyPremium, Deductible, and NumberOfTransactions.
- Design a star schema for this problem. See Figure 9-10 for the format you should follow.
- Estimate the number of rows in the fact table, using the assumptions stated previously.
- Estimate the total size of the fact table (in bytes), assuming an average of 10 bytes per field.
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Consider the following entity relationship diagram.
Booking
Employee
Room
Building
• Booking ID
• Employee ID
• Building ID
• Room ID
• First Name
• Room ID P
• Name
Description
• Employee ID
• Name
Last Name
• Date
• Campus Zone
• Email Address
• Capacity
• Start Time
• Map Coordinates
Phone
• Bookable
• End Time
For each statement below, use the drop-down box to indicate whether it is true (answer 1) or false (answer2), according to the design decisions encoded in the ERD.
Every booking is associated with exactly one employee.
✓ Every employee is associated with at most one booking.
✓ A building may contain no rooms that are recorded in the database.
Each room may have many bookings.
1. True
✓ A room must have at least one booking.
2. False
✓ A booking can be associated with many employees.
An employee may have no phone number recorded.
✓ A room must have its capacity recorded.
✓ A building is uniquely identified by its map coordinates.
I need help building an ERD in Crow's Foot notation with the following (If possible show me any many-many and optional/mandatory relationship) :
The model above needs some improvement. Where you can apply all the normalization rules to attributes. Furthermore, you also need to explain entities and relations between them, and the purpose of attributes by showing why and how they exist ?.
Chapter 9 Solutions
Modern Database Management
Ch. 9 - Prob. 9.1RQCh. 9 - Prob. 9.2RQCh. 9 - Prob. 9.3RQCh. 9 - List the five major trends that necessitate data...Ch. 9 - Prob. 9.5RQCh. 9 - Prob. 9.6RQCh. 9 - Prob. 9.7RQCh. 9 - Prob. 9.8RQCh. 9 - Prob. 9.9RQCh. 9 - Prob. 9.10RQ
Ch. 9 - List four objectives of derived data.Ch. 9 - Prob. 9.12RQCh. 9 - Prob. 9.13RQCh. 9 - Explain the pros and cons of logical data marts.Ch. 9 - Prob. 9.15RQCh. 9 - What is a helper table, and why is it often used...Ch. 9 - Describe the characteristics of a surrogate key as...Ch. 9 - Prob. 9.18RQCh. 9 - What is the purpose of conformed dimensions for...Ch. 9 - Prob. 9.20RQCh. 9 - Prob. 9.21RQCh. 9 - Prob. 9.22RQCh. 9 - Prob. 9.23RQCh. 9 - Prob. 9.24RQCh. 9 - Prob. 9.25RQCh. 9 - Describe the current key trends in data...Ch. 9 - Discuss the benefits of offering data warehousing...Ch. 9 - Prob. 9.28RQCh. 9 - List six typical characteristics of reconciled...Ch. 9 - Prob. 9.30RQCh. 9 - Prob. 9.31RQCh. 9 - Prob. 9.32RQCh. 9 - Prob. 9.33RQCh. 9 - Describe some field-level and record-level data...Ch. 9 - Prob. 9.35PAECh. 9 - Prob. 9.36PAECh. 9 - Prob. 9.37PAECh. 9 - Prob. 9.38PAECh. 9 - You are to construct a star schema for Simplified...Ch. 9 - Simplified Automobile Insurance Company would like...Ch. 9 - Prob. 9.41PAECh. 9 - Prob. 9.42PAECh. 9 - Prob. 9.43PAECh. 9 - Prob. 9.45PAECh. 9 - Prob. 9.46PAECh. 9 - Prob. 9.47PAECh. 9 - Prob. 9.48PAECh. 9 - Prob. 9.49PAECh. 9 - Prob. 9.50PAECh. 9 - Prob. 9.51PAECh. 9 - Prob. 9.52PAECh. 9 - Prob. 9.53PAECh. 9 - Prob. 9.54PAE
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