
Essentials of Materials Science and Engineering, SI Edition
4th Edition
ISBN: 9781337672078
Author: ASKELAND, Donald R., WRIGHT, Wendelin J.
Publisher: Cengage Learning
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Question
Chapter 9, Problem 9.117CP
Interpretation Introduction
Interpretation:
The value of free energy for a heterogeneous process as a function of angle needs to be determined. The variation in the value with respect to angle needs to be explained.
Concept Introduction:
Homogenous nucleation is the process in which nuclei are randomly and spontaneously generated grows irreversibly to form a new phase, homogenous nucleation that is independent of any lattice defect is very rare. It can be only become viable if the strain energy and surface energy involved in creating a nucleus issmall.
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Question 2
A transistor is used as a switch and the waveforms are shown in Figure 2. The parameters are
Vcc = 225 V, VBE(sat) = 3 V, IB = 8 A, VCE(sat) = 2 V, Ics = 90 A, td = 0.5 µs, tr = 1 µs, ts = 3 µs, tƒ
= 2 μs, and f
10 kHz. The duty cycle is k 50%. The collector- emitter leakage current is
ICEO = 2 mA. Determine the power loss due to the collector current:
=
=
=
(a) during turn-on ton = td + tr
VCE
Vcc
(b) during conduction period tn
V CE(sat)
0
toff"
ton
Ics
0.9 Ics
(c) during turn-off toff = ts + tf
(d) during off-time tot
(e) the total average power losses PT
ICEO
0
IBS
0
Figure 2
V BE(sat)
0
主
*
td
tr
In
Is
If
to
iB
VBE
T= 1/fs
Question 1:
The beta (B) of the bipolar transistor shown in Figure 1 varies from 12 to 60. The load resistance
is Rc = 5. The dc supply voltage is VCC = 40 V and the input voltage to the base circuit is
VB = 5 V. If VCE(sat) = 1.2 V, VBE(sat) = 1.6 V, and RB = 0.8 2, calculate:
(a) the overdrive factor ODF.
(b) the forced ẞ
(c) the power loss in the transistor PT.
IB
VB
RB
+
V BE
RC
Vcc'
Ic
+
IE
Figure 1
VCE
The given beam has continuous lateral support. If the live load is twice the dead load, what is the
maximum total service load, in kips / ft, that can be supported? A992 steel is used: Fy = 50 ksi,
Fu=65 ksi. Take L = 30 ft.
bf
For W40 x 149:
2tf
=
7.11,
=
=
54.3, Z 598 in.³
tw
W
W40 X 149
L
(Express your answers to three significant figures.)
a. Use LRFD.
Wtotal =
kips/ft
b. Use ASD.
Wtotal
kips/ft
Chapter 9 Solutions
Essentials of Materials Science and Engineering, SI Edition
Ch. 9 - Prob. 9.1PCh. 9 - Prob. 9.2PCh. 9 - Prob. 9.3PCh. 9 - Prob. 9.4PCh. 9 - Prob. 9.5PCh. 9 - Prob. 9.6PCh. 9 - Prob. 9.7PCh. 9 - Prob. 9.8PCh. 9 - Prob. 9.9PCh. 9 - Prob. 9.10P
Ch. 9 - Prob. 9.11PCh. 9 - Prob. 9.12PCh. 9 - Prob. 9.13PCh. 9 - Prob. 9.14PCh. 9 - Prob. 9.15PCh. 9 - Prob. 9.16PCh. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Prob. 9.19PCh. 9 - Prob. 9.20PCh. 9 - Prob. 9.21PCh. 9 - Prob. 9.22PCh. 9 - Prob. 9.23PCh. 9 - Prob. 9.24PCh. 9 - Prob. 9.25PCh. 9 - Prob. 9.26PCh. 9 - Prob. 9.27PCh. 9 - Prob. 9.28PCh. 9 - Prob. 9.29PCh. 9 - Prob. 9.30PCh. 9 - Prob. 9.31PCh. 9 - Prob. 9.32PCh. 9 - Prob. 9.33PCh. 9 - Prob. 9.34PCh. 9 - Prob. 9.35PCh. 9 - Prob. 9.36PCh. 9 - Prob. 9.37PCh. 9 - Prob. 9.38PCh. 9 - Prob. 9.39PCh. 9 - Prob. 9.40PCh. 9 - Prob. 9.41PCh. 9 - Prob. 9.42PCh. 9 - Prob. 9.43PCh. 9 - Prob. 9.44PCh. 9 - Prob. 9.45PCh. 9 - Prob. 9.46PCh. 9 - Prob. 9.47PCh. 9 - Prob. 9.48PCh. 9 - Prob. 9.49PCh. 9 - Prob. 9.50PCh. 9 - Prob. 9.51PCh. 9 - Prob. 9.52PCh. 9 - Prob. 9.53PCh. 9 - Prob. 9.54PCh. 9 - Prob. 9.55PCh. 9 - Prob. 9.56PCh. 9 - Prob. 9.57PCh. 9 - Prob. 9.58PCh. 9 - Prob. 9.59PCh. 9 - Prob. 9.60PCh. 9 - Prob. 9.61PCh. 9 - Prob. 9.62PCh. 9 - Prob. 9.63PCh. 9 - Prob. 9.64PCh. 9 - Prob. 9.65PCh. 9 - Prob. 9.66PCh. 9 - Prob. 9.67PCh. 9 - Prob. 9.68PCh. 9 - Prob. 9.69PCh. 9 - Prob. 9.70PCh. 9 - Prob. 9.71PCh. 9 - Prob. 9.72PCh. 9 - Prob. 9.73PCh. 9 - Prob. 9.74PCh. 9 - Prob. 9.75PCh. 9 - Prob. 9.76PCh. 9 - Prob. 9.77PCh. 9 - Prob. 9.78PCh. 9 - Prob. 9.79PCh. 9 - Prob. 9.80PCh. 9 - Prob. 9.81PCh. 9 - Prob. 9.82PCh. 9 - Prob. 9.83PCh. 9 - Prob. 9.84PCh. 9 - Prob. 9.85PCh. 9 - Prob. 9.86PCh. 9 - Prob. 9.87PCh. 9 - Prob. 9.88PCh. 9 - Prob. 9.89PCh. 9 - Prob. 9.90PCh. 9 - Prob. 9.91PCh. 9 - Prob. 9.92PCh. 9 - Prob. 9.93PCh. 9 - Prob. 9.94PCh. 9 - Prob. 9.95PCh. 9 - Prob. 9.96PCh. 9 - Prob. 9.97PCh. 9 - Prob. 9.98PCh. 9 - Prob. 9.99PCh. 9 - Prob. 9.100PCh. 9 - Prob. 9.101PCh. 9 - Prob. 9.102PCh. 9 - Prob. 9.103PCh. 9 - Prob. 9.104PCh. 9 - Prob. 9.105PCh. 9 - Prob. 9.106PCh. 9 - Prob. 9.107PCh. 9 - Prob. 9.108PCh. 9 - Prob. 9.109PCh. 9 - Prob. 9.110PCh. 9 - Prob. 9.111DPCh. 9 - Prob. 9.112DPCh. 9 - Prob. 9.113DPCh. 9 - Prob. 9.114DPCh. 9 - Prob. 9.115DPCh. 9 - Prob. 9.116CPCh. 9 - Prob. 9.117CPCh. 9 - Prob. 9.118CPCh. 9 - Prob. K9.1KPCh. 9 - Prob. K9.2KP
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