The band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
The band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
Solution Summary: The author explains that the band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated.
The band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated.
Concept introduction:
According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation,
MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10
Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
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kJ
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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