The wavelength of the light emitted by Aluminium phosphide diode has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
The wavelength of the light emitted by Aluminium phosphide diode has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
Solution Summary: The author explains that the wavelength of the light emitted by Aluminium phosphide diode has to be calculated. The energy gap between the valence band and conduction band is represented by Planck’s equation
The wavelength of the light emitted by Aluminium phosphide diode has to be calculated.
Concept introduction:
According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation,
Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating
the reactants?
O
? A
. If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like.
. If your answer is no, check the box under the drawing area instead.
Explanation
Check
Click and drag to start drawing a structure.
ㅇ
80
F5
F6
A
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In methyl orange preparation, if the reaction started with 0.5 mole of sulfanilic acid to form the diazonium salt of this compound and then it converted to methyl orange [0.2 mole]. If the efficiency of the second step was 50%, Calculate: A. Equation(s) of Methyl Orange synthesis: Diazotization and coupling reactions. B. How much diazonium salt was formed in this reaction? C. The efficiency percentage of the diazotization reaction D. Efficiency percentage of the whole reaction.