EBK COMPUTER SCIENCE: AN OVERVIEW
12th Edition
ISBN: 8220102744196
Author: BRYLOW
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Expert Solution & Answer
Chapter 9, Problem 33CRP
Explanation of Solution
Given code:
TEMP1 <- JOIN EMPLOYEE and ASSIGNMENT
where EMPLOYEE.EmpId =
ASSIGNMENT.EmpId
TEMP2 <- SELECT from TEMP1 where
TermDate = '*'
RESULT <- PROJECT name, StartDate
from TEMP2
Code Explanation:
- The given code is used to lists the “name” and “StartDate” from relations “EMPLOYEE” and “ASSIGNMENT” where the value of “EmpId” is equal in both relations and the value of “TermDate” is “*”.
- From the given code, the statement “TEMP1 <- JOIN EMPLOYEE and ASSIGNMENT where EMPLOYEE.EmpId = ASSIGNMENT...
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Subject: Database management system
Explain in easy way with write handwritten note
Test if the following schedule is conflict serializable or not and explain
R1 (A), R2 (D), W1 (B), R2 (B), W3 (B), R4 (B), W2 (C), R5 (C), W4 (E), R5 (E), W5 (B).
Subject: Database management system
Explain in easy way with write handwritten note
Test if the following schedule is conflict serializable or not and explain
R1 (A), R2 (D), W1 (B), R2 (B), W3 (B), R4 (B), W2 (C), R5 (C), W4 (E), R5 (E), W5 (B).
Subject: Database management system
Explain in easy way with write handwritten note
a. What is lossy decomposition? Check whether the following decompositions are lossy or lossless.
(i) Let R=ABCD, R1 = AD, R2 = AB, R3 = BE, R4 = CDE, R5 = AE, F={ A->C, B- >C, C->D, DE->C, CE->A}
(ii) R (XYZWQ), FD= {X->Z, Y->Z, Z->W, WQ->Z, ZQ-> X, R1 (XW), R2 (XY), R3 (YQ) , R4 (ZWQ), R5 (XQ)
b. Eliminate redundant FDs from
(i) F={X->Y, Y->X, Y->Z, Z->Y, X->Z, Z->X}
(ii) F = {X->YZ, ZW->P, P->Z, W->XPQ, XYQ, YW, WQ ->YZ}
Chapter 9 Solutions
EBK COMPUTER SCIENCE: AN OVERVIEW
Ch. 9.1 - Identify two departments in a manufacturing plant...Ch. 9.1 - Prob. 2QECh. 9.1 - Summarize the roles of the application software...Ch. 9.2 - Prob. 1QECh. 9.2 - Prob. 2QECh. 9.2 - Prob. 4QECh. 9.2 - Prob. 5QECh. 9.2 - Prob. 6QECh. 9.3 - Prob. 1QECh. 9.3 - What is a persistent object?
Ch. 9.3 - Identify some classes as well as some of their...Ch. 9.3 - Prob. 4QECh. 9.4 - Prob. 1QECh. 9.4 - Prob. 2QECh. 9.4 - Prob. 3QECh. 9.4 - Prob. 4QECh. 9.4 - Prob. 5QECh. 9.4 - Prob. 6QECh. 9.5 - Prob. 1QECh. 9.5 - Prob. 2QECh. 9.5 - Prob. 3QECh. 9.5 - Prob. 4QECh. 9.5 - Prob. 5QECh. 9.5 - Prob. 6QECh. 9.5 - Prob. 7QECh. 9.6 - Prob. 1QECh. 9.6 - Give an additional example of a pattern that might...Ch. 9.6 - Prob. 3QECh. 9.6 - How does data mining differ from traditional...Ch. 9.7 - Prob. 1QECh. 9.7 - Prob. 2QECh. 9.7 - Prob. 3QECh. 9.7 - Prob. 4QECh. 9 - Prob. 1CRPCh. 9 - Prob. 2CRPCh. 9 - Prob. 3CRPCh. 9 - Prob. 4CRPCh. 9 - Prob. 5CRPCh. 9 - Prob. 6CRPCh. 9 - Prob. 7CRPCh. 9 - Prob. 8CRPCh. 9 - Prob. 9CRPCh. 9 - Prob. 10CRPCh. 9 - Prob. 11CRPCh. 9 - Prob. 12CRPCh. 9 - Using the commands SELECT, PROJECT, and JOIN,...Ch. 9 - Answer Problem 13 using SQL. PROBLEM 13 13. Using...Ch. 9 - Prob. 15CRPCh. 9 - Prob. 16CRPCh. 9 - Prob. 17CRPCh. 9 - Prob. 18CRPCh. 9 - Prob. 19CRPCh. 9 - Empl Id Name Address SSN Job Id Job Title Skill...Ch. 9 - Empl Id Name Address SSN Job Id Job Title Skill...Ch. 9 - Prob. 22CRPCh. 9 - Prob. 23CRPCh. 9 - Prob. 24CRPCh. 9 - Prob. 25CRPCh. 9 - Write a sequence of instructions (using the...Ch. 9 - Prob. 27CRPCh. 9 - Prob. 28CRPCh. 9 - Prob. 29CRPCh. 9 - Prob. 30CRPCh. 9 - Prob. 31CRPCh. 9 - Prob. 32CRPCh. 9 - Prob. 33CRPCh. 9 - Prob. 34CRPCh. 9 - Prob. 35CRPCh. 9 - Prob. 36CRPCh. 9 - Prob. 37CRPCh. 9 - Prob. 38CRPCh. 9 - Prob. 39CRPCh. 9 - Prob. 40CRPCh. 9 - Prob. 41CRPCh. 9 - Prob. 42CRPCh. 9 - Prob. 43CRPCh. 9 - Prob. 44CRPCh. 9 - Prob. 45CRPCh. 9 - Prob. 46CRPCh. 9 - Prob. 47CRPCh. 9 - Prob. 48CRPCh. 9 - Prob. 49CRPCh. 9 - Prob. 50CRPCh. 9 - Prob. 51CRPCh. 9 - Prob. 52CRPCh. 9 - Prob. 53CRPCh. 9 - Prob. 54CRPCh. 9 - Prob. 55CRPCh. 9 - Prob. 56CRPCh. 9 - Prob. 57CRPCh. 9 - Prob. 58CRPCh. 9 - Prob. 59CRPCh. 9 - Prob. 60CRPCh. 9 - Prob. 61CRPCh. 9 - Prob. 62CRPCh. 9 - Prob. 1SICh. 9 - Prob. 2SICh. 9 - Prob. 3SICh. 9 - Prob. 4SICh. 9 - Prob. 5SICh. 9 - Prob. 6SICh. 9 - Prob. 7SICh. 9 - Prob. 8SICh. 9 - Prob. 9SICh. 9 - Prob. 10SI
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- Subject: DBMS Explain in easy way and do not use chatgpt A database is being constructed to keep track of the teams and games of a sports league. A team has a number of players, not all of whom participate in each game. It is desired to keep track of the players participating in each game for each team, the positions they played in that game, and the result of the game. Design an ER schema diagram for this application, stating any assumptions you make. Choose your favorite sport (e.g., soccer, baseball, football).arrow_forwardhelp with this pleasearrow_forwardFor the control system plot root Locus and find the D gain of stability? by Matlab Ris Kp (5+3) S+5 (s+1) +CUST s(S+2) (565+18) 5-1 5²+35+4arrow_forward
- CIS 115 Introduction to C++ May I please have a written review expressing my gratitude for a tutor that has given me guidance throughout the computer programming course? Thank you so much!arrow_forwardMath 130 Introduction to Java programming May I please have a written review expressing my gratitude for a tutor that has given my guidance throughout my computer programming course? Thank youarrow_forwardPlease help me translate the java code to jack codearrow_forward
- Translate the following VM commands to Assembly instructions: □ push constant 1 □ push constant 5arrow_forwardSuppose the state of the argument and local memory segments are as follows: argument local stack 0 0 9 sp-> 256 1 257 1 14 2 258 259 Now consider the following VM code: 1 push constant 2 pop local @ 3 push constant 15 4 pop local 1 5 push local 1 6 push argument 1 7 gt 8 pop local 2 9 push local 0 10 push argument 0 11 add 12 pop local 0 13 push local 1 14 push local 1 15 push constant 1 16 sub 17 add 18 pop local 1 What will be the value of local 1 after the VM code has executed?arrow_forwardSuppose the state of the RAM is as follows and the adjacent assembly code will execute: RAM 0 3 1 2 2 0 فيا 3 6 456 5 1 4 1234567 $1 A = M A = M A = M D = M @4 M = D What will be the value of the RAM[4] following the assembly code execution?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Programming Logic & Design ComprehensiveComputer ScienceISBN:9781337669405Author:FARRELLPublisher:Cengage
Programming Logic & Design Comprehensive
Computer Science
ISBN:9781337669405
Author:FARRELL
Publisher:Cengage