EBK COMPUTER SCIENCE: AN OVERVIEW
12th Edition
ISBN: 8220102744196
Author: BRYLOW
Publisher: PEARSON
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Chapter 9, Problem 12CRP
Explanation of Solution
(a)
Given instruction is,
RESULT PROJECT W from X
The appearance of the relation “RESULT” after execution of the instruction are as follows,
Explanation of Solution
(b)
Given instruction is,
RESULT SELECT from X where W=5
The appearance of the relation “RESULT” after execution of the instruction are as follows,
Explanation of Solution
(c)
Given instruction is,
RESULT PROJECT S from Y
The appearance of the relation “RESULT” after execution of the instruction are as follows,
Explanation of Solution
(d)
Given instruction is,
RESULT JOIN X and Y where X.W Y.R
The appearance of the relation “RESULT” after execution of the instruction are as f...
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Let R₁ and R₂ be the relations on X={a,b,c},
R₁={ (b,a), (c,b), (a,c) }
R₂={ (a,c), (b,c)}
R₁-¹=
R₂ ° R₁=
32 of 40
Suppose attribute A is a key in the relation R.
Which of the following statements is not correct?
Select one:
O A is a key in (oc=99(R))
O A is a key in R-S
O A is a key in R US
O All of the four statements.
None of the four statements.
O A is a Key in (T ABC(R))
Exercise 4:
R1 = {(a, b) E R² | a > b}, the “greater than" relation,
R2 = {(a, b) E R² | a > b}, the “greater than or equal to" relation,
R3 = {(a, b) E R² | a < b}, the "less than" relation,
R4 = {(a, b) E R² | a
Chapter 9 Solutions
EBK COMPUTER SCIENCE: AN OVERVIEW
Ch. 9.1 - Identify two departments in a manufacturing plant...Ch. 9.1 - Prob. 2QECh. 9.1 - Summarize the roles of the application software...Ch. 9.2 - Prob. 1QECh. 9.2 - Prob. 2QECh. 9.2 - Prob. 4QECh. 9.2 - Prob. 5QECh. 9.2 - Prob. 6QECh. 9.3 - Prob. 1QECh. 9.3 - What is a persistent object?
Ch. 9.3 - Identify some classes as well as some of their...Ch. 9.3 - Prob. 4QECh. 9.4 - Prob. 1QECh. 9.4 - Prob. 2QECh. 9.4 - Prob. 3QECh. 9.4 - Prob. 4QECh. 9.4 - Prob. 5QECh. 9.4 - Prob. 6QECh. 9.5 - Prob. 1QECh. 9.5 - Prob. 2QECh. 9.5 - Prob. 3QECh. 9.5 - Prob. 4QECh. 9.5 - Prob. 5QECh. 9.5 - Prob. 6QECh. 9.5 - Prob. 7QECh. 9.6 - Prob. 1QECh. 9.6 - Give an additional example of a pattern that might...Ch. 9.6 - Prob. 3QECh. 9.6 - How does data mining differ from traditional...Ch. 9.7 - Prob. 1QECh. 9.7 - Prob. 2QECh. 9.7 - Prob. 3QECh. 9.7 - Prob. 4QECh. 9 - Prob. 1CRPCh. 9 - Prob. 2CRPCh. 9 - Prob. 3CRPCh. 9 - Prob. 4CRPCh. 9 - Prob. 5CRPCh. 9 - Prob. 6CRPCh. 9 - Prob. 7CRPCh. 9 - Prob. 8CRPCh. 9 - Prob. 9CRPCh. 9 - Prob. 10CRPCh. 9 - Prob. 11CRPCh. 9 - Prob. 12CRPCh. 9 - Using the commands SELECT, PROJECT, and JOIN,...Ch. 9 - Answer Problem 13 using SQL. PROBLEM 13 13. Using...Ch. 9 - Prob. 15CRPCh. 9 - Prob. 16CRPCh. 9 - Prob. 17CRPCh. 9 - Prob. 18CRPCh. 9 - Prob. 19CRPCh. 9 - Empl Id Name Address SSN Job Id Job Title Skill...Ch. 9 - Empl Id Name Address SSN Job Id Job Title Skill...Ch. 9 - Prob. 22CRPCh. 9 - Prob. 23CRPCh. 9 - Prob. 24CRPCh. 9 - Prob. 25CRPCh. 9 - Write a sequence of instructions (using the...Ch. 9 - Prob. 27CRPCh. 9 - Prob. 28CRPCh. 9 - Prob. 29CRPCh. 9 - Prob. 30CRPCh. 9 - Prob. 31CRPCh. 9 - Prob. 32CRPCh. 9 - Prob. 33CRPCh. 9 - Prob. 34CRPCh. 9 - Prob. 35CRPCh. 9 - Prob. 36CRPCh. 9 - Prob. 37CRPCh. 9 - Prob. 38CRPCh. 9 - Prob. 39CRPCh. 9 - Prob. 40CRPCh. 9 - Prob. 41CRPCh. 9 - Prob. 42CRPCh. 9 - Prob. 43CRPCh. 9 - Prob. 44CRPCh. 9 - Prob. 45CRPCh. 9 - Prob. 46CRPCh. 9 - Prob. 47CRPCh. 9 - Prob. 48CRPCh. 9 - Prob. 49CRPCh. 9 - Prob. 50CRPCh. 9 - Prob. 51CRPCh. 9 - Prob. 52CRPCh. 9 - Prob. 53CRPCh. 9 - Prob. 54CRPCh. 9 - Prob. 55CRPCh. 9 - Prob. 56CRPCh. 9 - Prob. 57CRPCh. 9 - Prob. 58CRPCh. 9 - Prob. 59CRPCh. 9 - Prob. 60CRPCh. 9 - Prob. 61CRPCh. 9 - Prob. 62CRPCh. 9 - Prob. 1SICh. 9 - Prob. 2SICh. 9 - Prob. 3SICh. 9 - Prob. 4SICh. 9 - Prob. 5SICh. 9 - Prob. 6SICh. 9 - Prob. 7SICh. 9 - Prob. 8SICh. 9 - Prob. 9SICh. 9 - Prob. 10SI
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- 5. For the following simple seven-activity project, develop a precedence network, calculate all relevant characteristics of each activity (ES, EF, LS, LF, TF), and calculate the project duration. Then draw a time-scaled network and under it a labor resource histogram for the ES. Do the same for the LS. In both cases, use the maximum allowable number of workers. Make adjustments to the noncritical activities, within the constraints of the ES and LF and the maximum and minimum workers allowed to provide what you feel is the best labor distribution. Please use Table B (Table B.pdf) Lastly, Explain in detail what do you feel is the biggest problem with the ES and LS configurations, and how has this been alleviated with your solution?arrow_forwardTask Description: consider the following relations for a university: Student (sid: integer, sname: string, GPA: real, dateOfBirth: date) Department (did: integer, dname: string, capacity: integer) Course (cid: integer, cname: string, credit: integer) Enroll (studentID: integer, courselD: integer, departmentID: Integer, enrollmentDate: date) studentlD, courselD, and departmentID in Enroll are foreign keys referencing the primary keys of the student, course, and department relations, respectively.arrow_forwardConsider the following relation. Instructor (ID , name, dept – name, salary) Department (dept – name , building ,budget) Classroom (building , roomno , capacity ) Teaches (ID , course – id , sec – id , semesters ) Course (course – id , title , dept – name , credit ) Student (ID , name dept – name ,fot – ored ) Takes (ID , course – id , sec – id, semester , year, grade) Write down queries expressed in SQL. 1) Find the name of all instructors who got the highest salary in their department. 2) Find the names of all the students whose total credits are greater than 100. 3) Find the course id and grades of all courses taken by any student. 4) Find all departments that have at least one instructor, and list – the name of the departments along with the number of instructorarrow_forward
- Task Description: consider the following relations for a university: Student (sid: integer, sname: string(100 chars), GPA: real, dateOfBirth: date, Did: integer, FirstYear: integer) Department (did: integer, dname: string(30 chars), capacity: integer) Course (cid: integer, cname: string(50 chars), credit: integer) Enroll (studentID: integer, courseID: integer, departmentID: integer, enrollmentDate: date, finalGrade: real) studentID, courseID, and departmentID in Enroll are foreign keys referencing the primary keys of the student, course, and department relations, respectively. Did in Student is a foreign key referencing the primary key of the department relation. Using SQL, develop and execute the following queries: 1- For each student with GPA between 2.5 (included) and 3.5 (included), display the student’s name, GPA,and his/her department ID. Sort the results by the students’ IDs in descending order. 2- For each student who joined the Computer Science department between 2018…arrow_forwardWhat does it mean to be related? How do you define a relation's properties?arrow_forwardgive correct option only.arrow_forward
- Draw an ER diagram to show the relationships among the tablesarrow_forwardRelations 2. Given: Relation R1 = {(a,a), (a,b), (c,b), (c,e), (d,b), (d,e), (e,e)} %3D Relation R2 = {(q1,q2), (q2,q3), (q2,q4), (q3,q6), (q4,q5), (q4,q3), (q5,q4), (q6,q6), (q6,q5)} %3D Answer the following: a. Draw the graph representation of relation R1. b. Draw the graph representation of relation R2.arrow_forwardConsider the following relation: TempID 111 222 333 444 555 666 TempName Joe Mike Sue Pat Bob Joe TemplD JobID J111 J222 J333 J444 J555 J666 TempName TEMP AGENCY Job TypelD T1 T2 T1 JobID T2 T1 T2 Job TypeDesc Bookkeepiing Answering calls Bookkeepiing Answering calls Bookkeepiing Answering calls • Each job has one job type, but multiple jobs can have the same job type • Each job is assigned to one employer. Same employer can have multiple jobs. 5a) In the figure below, indicate functional dependencies by drawing lines with arrows. -| Some of the requirements that this table is based on are as follows: • Each temporary worker has a unique TempID, and a non-unique TempName. • Each employer has a unique EID, and a non-unique EName. • Each job has a unique JobID, and a job type. • Each job type has a unique JobTypeID and a non-unique job type description (JobTypeDesc). • Each temporary worker is assigned to only one job. EID E1 E1 E2 E2 E2 E1 Job TypeID Job TypeDesc Ename Mid Bank Mid Bank…arrow_forward
- Draw an ER diagram that captures the following information: A book identified by (unique Id number, a title and one or more authors), A library identified by (unique name and adders), A borrower has a name and a unique ID code. The library service may own several copies of a given book. A borrower can have many books on loan, but each copy of a book can only be on loan to one borrower. A borrower could borrow the same book on several occasions, but it is assumed that each such loan will take place on a different date. *arrow_forwardDesign the relation schemesarrow_forwardwrite this in relation algebra: SELECT s.sname FROM student s, reservation r WHERE s.sid!=r.sidarrow_forward
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