Engineering Economy
16th Edition
ISBN: 9780133582819
Author: Sullivan
Publisher: DGTL BNCOM
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Question
Chapter 9, Problem 29CS
To determine
Calculate the annual worth.
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If a replacement study is performed and the defender is selected for retention for nD years, explain what should be done 1 year later if a new challenger is identified.
A large city in mid-west needs to buy a street-cleaning
machine. A used vehicle will cost $75000 and has a
market value of $20000 after its five-year life. A new
system cost $150000 and has a market value of
$40000 after five-years. The new system has some
features that reduce labor hours compared with used
system. the used system requires labor hours of 8 hours
per day and 20 days per month. the labor costs are $50
per hour. the MARR is 12%. if the new system is
expected to be able to reduce labor hours by 20%
compared with the used system, which system should
the city purchase? and how many hours must the
system be operated at the break even?
In replacement analysis, the "economic lifetime" of a capital equipment is
A. the service life that results in the lowest EUAC of the asset
B. the service life at which EUAC(capital recovery) = EUAC(Operation & maintenance costs)
C. the minimum service life required to recover the initial capital investment
Chapter 9 Solutions
Engineering Economy
Ch. 9 - Prob. 1PCh. 9 - Prob. 2PCh. 9 - Prob. 3PCh. 9 - Prob. 4PCh. 9 - Prob. 5PCh. 9 - Prob. 6PCh. 9 - Prob. 7PCh. 9 - A city water and waste-water department has a...Ch. 9 - Prob. 9PCh. 9 - Prob. 10P
Ch. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Use the PW method to select the better of the...Ch. 9 - Prob. 14PCh. 9 - Prob. 15PCh. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 20PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - Prob. 25PCh. 9 - Prob. 26PCh. 9 - Prob. 27SECh. 9 - Prob. 28SECh. 9 - Prob. 29CSCh. 9 - Prob. 30CSCh. 9 - Prob. 31CSCh. 9 - Prob. 32FECh. 9 - Prob. 33FECh. 9 - Prob. 34FECh. 9 - Prob. 35FECh. 9 - Prob. 36FE
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- Typically, there are two alternatives in a replacement analysis. One alternative is to replace the defender now. The other alternative is which of the following? A. Keep the defender for its remaining useful life.B Keep the defender for another year and then reexamine the situation. C Keep the defender until an improved challenger better than the current challenger comes to marketD. Keep the defender as long as it’s operational.arrow_forwardPlease answer fastarrow_forwardhelp please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all workingarrow_forward
- A specialty concrete mixer used in construction was purchased for $300,000 7 years ago. Its annual O&M costs are $105,000. At the end of the 8-year planning horizon, the mixer will have a salvage value of $5,000. If the mixer is replaced, a new mixer will require an initial investment of $375,000 and at the end of the 8-year planning horizon, the new mixer will have a salvage value of $45,000. Its annual O&M cost will be only $40,000 due to newer technology. Use an EUAC measure and a MARR of 15% to see if the concrete mixer should be replaced if the old mixer is sold for its market value of $65,000. Solve, a. Use the cash flow approach (insider’s viewpoint approach). b. Use the opportunity cost approach (outsider’s view point approach).arrow_forwardhow to get number in red arrow?arrow_forwardA replacement analysis is most objectively conducted from the viewpoint of:a. an outsider.b. a consultant.c. a non-owner.d. any of the above.arrow_forward
- Economics A commercial 3D printer is purchased for $310,000. The salvage value of the printer decreases by 45% each year that it is held. The cost to operate and maintain the machine the first year it is used is $12,000; these costs increase by $5,500 each year. What is the optimal replacement interval and minimum EUAC for the printer, assuming a MARR of 11% is used? ORI: years EUAC*: $arrow_forwardDo the operating costs differ between the defender and challenger? Explain how?arrow_forwardA 5 year-old tooling kit that was purchased new for $9000 has a current market value of $4000 and expected 0&M costs of $3000, increasing by $1200 per year. Future market values are expected to decline by 25% annually (going forward). The kit can be used for another 3 years at most. The optimal replacement kit costs $8000 and has 0&M costs starting at $2500 per year, increasing by $2000 per year. Salvage value for the new kit at the end of the first year is $4000 and falls by $1000 per year thereafter (until zero). The new model kit will be needed indefinitely. Assume a unique minimum AEC~(15%) for both kits (both the current and replacement kit). The MARR is 15%. 1) What is the AECC• ? a) Less than 6925.70 b) 6925.70-6945.70 c) 6945.70-6965.70 ) d) 6965.70-6985.70 e) More than 6985.70arrow_forward
- What is the book value (to the nearest cent) for the asset in year 1 if straight-line method is used? Cost of $50,000 Asset Useful Life 6 Salvage $4,000 Valuearrow_forwardPlease solve this in a copy with all process. Not in excel. If not done as instructed, I will down vote it.arrow_forward3. Angstrom Technologies intends for the company to use the newest and finest equipment in its labs. Precision measurement equipment was purchased 7 years ago for $160,000. Last year a replacement study was performed with the decision to retain for 3 more years. The situation has changed. The equipment is estimated to have a value of $8000 if "scavenged" for parts now or anytime in the future. If kept in service, it can be minimally upgraded at a cost of $43,000 to make it usable for up to 2 more years. Its operating cost is estimated at $22,000 the first year and $25,000 the second year. Alternatively, the company can purchase a new system that will have an equivalent annual worth of $47,063 per year over its ESL. The company uses a MARR of 10% per year. Use annual worth analysis to determine when the company should replace the machine.arrow_forward
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