Engineering Economy
16th Edition
ISBN: 9780133582819
Author: Sullivan
Publisher: DGTL BNCOM
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Chapter 9, Problem 5P
To determine
Calculate the equivalent annual value.
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A building supplies distributor purchased a gasoline-powered forklift truck 4 years ago for $8,000. At that time, the estimated useful life was 8 years with a salvage value of $800 at the end of this time. The truck can now be sold for $2,500. For this truck, average annual O&M expenses for year j have been Cj = $2, 000 + $400(j − 1) Now the distributor is considering the purchase of a smaller battery-powered truck for $6,500. The estimated life is 10 years, with the salvage value decreasing by $600 each year. Average annual O&M expenses are expected to be $1,200. If a MARR of 10% is assumed and a 4-year planning horizon is adopted, based on an annual worth cash flow approach should the replacement be made now?
Assume the MARR is 10% per year for this analysis. A presently owned machine that was purchased 8 years ago for $450,000 is under consideration for replacement. It has an annual operating cost of $120,000 per year and a salvage value of $40,000 whenever it is replaced. The challenger has a first cost of $670,000, an expected annual operating cost of $94,000, and a salvage value of $60,000 after its 10-year economic life. The breakeven market value of the presently owned machine required to make the AW values of the two machines the same, if the presently owned machine is kept for 5 more years and then replaced with the challenger that has the same AW, is closest to: (a) $196,340 (b) $255,390 (c) $325,360 (d ) $394,770
An engineer calculated the AW values shown for retaining a presently owned
machine additional years.
A challenger has an ESL of 4 years with AW = $-60,000 per year.
Assuming all future costs remain the same, when should the company replace the
defender?
The MARR is 12% per year. Assume used machines like the one presently owned
will always be available.
Years Retained
12345
a) at year 5
b) at year 4
c) at year 1
d) at year 3
AW of Defender,
$
-77,000
-63,000
-58,000
-64,000
-70,000
Chapter 9 Solutions
Engineering Economy
Ch. 9 - Prob. 1PCh. 9 - Prob. 2PCh. 9 - Prob. 3PCh. 9 - Prob. 4PCh. 9 - Prob. 5PCh. 9 - Prob. 6PCh. 9 - Prob. 7PCh. 9 - A city water and waste-water department has a...Ch. 9 - Prob. 9PCh. 9 - Prob. 10P
Ch. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Use the PW method to select the better of the...Ch. 9 - Prob. 14PCh. 9 - Prob. 15PCh. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 20PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - Prob. 25PCh. 9 - Prob. 26PCh. 9 - Prob. 27SECh. 9 - Prob. 28SECh. 9 - Prob. 29CSCh. 9 - Prob. 30CSCh. 9 - Prob. 31CSCh. 9 - Prob. 32FECh. 9 - Prob. 33FECh. 9 - Prob. 34FECh. 9 - Prob. 35FECh. 9 - Prob. 36FE
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- Veritas Inc. has decided to acquire a new Hydraulic Excavator. It has three options. Caterpillar: purchase cost of $354,055 and operating costs of $28,121 per year (paid at the end of each year). John Deere: purchase cost of $288,413 and operating costs of $21,091 per year (paid at the end of each year). Volvo: purchase cost of $323,238 and operating costs of $15,484 per year (paid at the end of each year). Assume that Geek Inc. has a budget of $335,269 and all excavators have a service life of 13 years. Based on the defender-challenger approach and given that the MARR is 10%, compute the incremental Benefit-Cost ratio of choosing the best excavator (note: round your answer to two decimal places; do not include spaces, dollar signs, or commas). Indicate your recommendation as follows: - answer "0" (without the commas) if your recommendation is the Caterpillar; - answer "1" (without the commas) if your recommendation is the John Deere; - write down as your answer the value of the…arrow_forwardA 2000-pound, counterbalanced, propane forklift can be purchased for $30,000. Due to the intended service use, the forklift’s market value drops 20% of its prior year’s value in Years 1 and 2 and then declines by 15% until Year 10 when it will have a scrap/market value of $1000. Maintenance of the forklift is $500 per year during Years 1 and 2 while the warranty is in place. In Year 3 it jumps to $750 and increases $750 per year thereafter. What is the optimal life of the forklift using i = 10%?arrow_forwardIn a replacement analysis problem, the following information is available Initial cost : 12.000 YTL Annual maintenance cost: None in the first three years 2.000 YTL at the end of the 4th year 2.000 YTL at the end of the 5th year 2,500 YTL per year after the 5th year will increase smoothly (at the end of the 6th year, 4.500 YTL 7.000 YTL at the end of the 7th year, etc. The scrap value in any given year is zero. Take the discount rate of 10% and ignore income taxes. Calculate the most economical life for this candidate equipment. A) 6 B) 2 C) 5 D) 8 E) 4arrow_forward
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