(a) Explanation Formula used: Lateral surface area of a cylinder is L = C h or L = 2 π r h = π d h . Volume of a cylinder is V = π r 2 h or V = 1 4 π d 2 h ≈ 0.7854 d 2 h . Where C is the circumference of the base, r is the radius of the base, d is the diameter of the base, and h is the altitude of the cylinder. Surface area of a sphere is A = 4 π r 2 or A = π d 2 . Where r is the radius of the base, d is the diameter of the base. Calculation: Surface area of four lower sides is, A = 2 ( 2 in × 11 in ) + 2 ( 2 in × 8 in ) = 76 in 2 By using the formula used find the lateral surface area as follows. L = p h L = ( 3 in + 2 in + 5.5 in + 3.2 in ) ( 8 in ) L = ( 13 (b) To determine The volume of the given pyramid frustum.

Mathematics for the Trades: A Guided Approach, Books a la Carte edition (11th Edition)

11th Edition

ISBN: 9780134765785

Author: Hal Saunders

Publisher: PEARSON

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Chapter 9, Problem 21APS

(a)

To determine

The total outside surface area of the pyramid frustum.

(b)

To determine

The volume of the given pyramid frustum.

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Chapter 9, Problem 20APS

Chapter 9, Problem 1BPS

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Chapter 9 Solutions

Mathematics for the Trades: A Guided Approach, Books a la Carte edition (11th Edition)

Ch. 9.1 - What is the perimeter of a regular hexagon with...Ch. 9.1 - Find the area:Ch. 9.1 - Find the volume of each of the following right...Ch. 9.1 - Find the volume of each of the following right...Ch. 9.1 - Find the volume of each of the following right...Ch. 9.1 - Find the volume of each of the following right...Ch. 9.1 - Prob. 5AE Ch. 9.1 - Find the volume of each of the following right...Ch. 9.1 - Find the volume of each of the following right...Ch. 9.1 - Find the volume of each of the following right...

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The total outside surface area of the pyramid frustum.

Solution Summary: The author calculates the outside surface area of the pyramid frustum and the volume of a cylinder.

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The total outside surface area of the pyramid frustum.

The volume of the given pyramid frustum.

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Chapter 9 Solutions