Campbell Essential Biology with Physiology (6th Edition)
6th Edition
ISBN: 9780134711751
Author: Eric J. Simon, Jean L. Dickey, Jane B. Reece
Publisher: PEARSON
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Chapter 9, Problem 17SQ
Summary Introduction
To explain: The type of offspring formed when a black short-haired male rabbit is mated with a brown long haired female rabbit, genotypes of the offspring formed, and the
Introduction: The rabbits have genes for long hair, short hair, black color and brown color of the body which forms a dihybrid cross. The crosses between these mice lead to the formation of the offspring.
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Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes?
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In certain species of flies, eye color is controlled by sim-·ple dominance by a single pair of alleles. A red-eyed fly was crossed with a white-eyed fly, both of whose parents had white eyes. All of their offspring (both female and male) had red eyes.a. Which is dominant, the allele for red eyesor the allele for white eyes?b. What is the genotype of the white-eyed parents?c. If the white-eyed parent was mated with one of the red-eyed offspring, what phenotypic ratio wouldyou expect regarding eye color?
In a certain breed of dog, the dominant, B, is required for black fur; it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic to the color locus and can inhibit pigment formation. The recessive allele, i, on the other hand, permits pigment deposition in the fur. What would be the phenotypes of the following sets of parents and what would be the results of the mating BBii x bbIi
1/4 black, 1/4 brown, 1/2 no color
1/2 black, 1/2 brown
1/2 black, 1/2 no color
1/3 black, 1/3 no color, 1/3 brown
Chapter 9 Solutions
Campbell Essential Biology with Physiology (6th Edition)
Ch. 9 - The genetic makeup of an organism is called its...Ch. 9 - Which of Mendels laws is represented by each...Ch. 9 - Prob. 3SQCh. 9 - Prob. 4SQCh. 9 - Prob. 5SQCh. 9 - Prob. 6SQCh. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Prob. 9SQCh. 9 - Prob. 10SQ
Ch. 9 - Prob. 11SQCh. 9 - Prob. 12SQCh. 9 - Incomplete dominance is seen in the inheritance of...Ch. 9 - Why was Henry VIII wrong to blame his wives for...Ch. 9 - Prob. 15SQCh. 9 - Prob. 16SQCh. 9 - Prob. 17SQCh. 9 - Prob. 18IMTCh. 9 - Prob. 19IMTCh. 9 - Prob. 20IMTCh. 9 - Prob. 21PSCh. 9 - Prob. 22PSCh. 9 - Prob. 23BSCh. 9 - Gregor Mendel never saw a gene, yet he concluded...Ch. 9 - Prob. 25BS
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- In Doodlewags (hypothetical creatures), the dominant allele S causes solid coat color; the recessive allele s results in white spots on a colored background. The black coat color allele B is dominant to the brown allele b, but these genes are expressed only in the genotype A-. Individuals that are aa are yellow regardless of B alleles. Six pups are produced in a mating between a solid yellow male and a solid brown female. Their phenotypes are 2 solid black, 1 spotted yellow, 1 spotted black and 2 solid brown. a. What are the genotypes of the male and female parents? Must show work/explain to get full credit. b. What genetic effect is being illustrated in part "a"? Explain in a minimum of 3 sentences.arrow_forwardIn cats, black fur (B) is dominant over brown fur (b). Also, striped fur (A) is dominant over solid colored fur (a). What is the phenotype of a cat with the genotype Bbaa? What combinations of gametes could the Bbaa cat make? If the Bbaa cat mated with a cat that was heterozygous for both the color and pattern genes, what fraction of their kittens would be likely to have solid brown fur? Hint: draw your square on a separate paper to figure it out.arrow_forwardIn Labrador retrievers, two genes determine fur color: the E gene and the B gene. Black fur (B) is dominant to brown fur (b). However, the presence of (ee) will overshadow and create a puppy with yellow fur. Create a Punnett square crossing 2 Labs that are heterozygous for both genes. What are the resulting phenotypes? Don’t forget to take epistasis into account!arrow_forward
- In Labrador retriever dogs, two alleles (B and b) determine whether coat colour will be black (B)or brown (b). Black coat colour is dominant. A second pair of alleles, E and e, are on a separatechromosome from B and b. The homozygous recessive condition, ee, prevents the expressionof either allele B or b, and produces a dog with a yellow-coloured coat. Some examples ofgenotypes and phenotypes for Labrador retrievers are shown below.Genotype PhenotypeBBEe blackbbEe brownBbee yellow Two dogs, each with the genotype, BbEe, were crossed. What is the percentageprobability that their offspring will have yellow coat colour? (Record your answer as awhole number percentage)arrow_forwardIn fruit flies, the allele for normal wings (V) is dominant to the allele for short wings (v). Suppose two fruit flies heterozygous for the trait are mated. What is the male fruit fly’s genotype and the female fruit fly’s genotype? What is the male fruit fly’s phenotype and the female fruit fly’s phenotype? What will be the genotypic ratio of the F1 generation? What will be the phenotypic ration of the F1 generation?arrow_forwardIn Labrador retrievers, two genes determine fur color: the E gene and the B gene. Black fur (B) is dominant to brown fur (b). However, the presence of (ee) will overshadow and create a puppy with yellow fur. Create a Punnett square crossing 2 Labs that are heterozygous for both genes. Then color code your Punnett Square based on the resulting phenotypes. Don’t forget to take epistasis into account!arrow_forward
- In cats, short hair (L) is dominant over long hair (l) and stripes (A) are dominant over solid color (a). A cat with genotype Ll Aa mates with a cat that is Ll aa, and they produce a litter of six kittens. What is the probability that four of the six kittens will have both long hair and stripes?arrow_forwardIn rabbits, black hair is due to a dominant allele B and brown hair to its recessive allele b. Short hair (H) is dominant to long hair (h). Show punnet squares In a cross between a homozygous black, longhaired rabbit and a brown, homozygous shorthaired one, what would the F1 generation look like? If you did not know the genotype of an F1 rabbit, you could determine its genotype by a test cross in which it is crossed with an animal with which phenotype AND genotype? If you carried out this test cross (from 2, using the F1 from 1), what phenotypes and in what ratio would you expect? What phenotypes in what ratio would be expected in the F2 generation of the cross in point 1?arrow_forwardHair length is incompletely dominant in Chihuahuas. If a homozygous long-haired Chi mates with a homozygous short-haired Chi, their heterozygous offspring have medium-length hair. If two heterozygous Chihuahuas mate, what is the probability that their pups will have long hair, medium hair, or short hair? L = long hair allele l = short hair allelearrow_forward
- The production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of a second independent gene turns the pigment to purple, but its recessive allele leaves it red. A fly producing no pigment has white eyes. Two pure lines were crossed with the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypes of the parents, the F1, and the F2.arrow_forwardIn cats, curled ears result from an allele (Cu) that is dominant over an allele (cu) for normal ears. Black color results from an independently assorting allele (G) that is dominant over an allele for gray (g). A gray cat homozygous for curled ears is mated with a homozygous black cat with normal ears. All the F1 cats are black and have curled ears. a. If two of the F1 cats mate, what phenotypes and proportions are expected in the F2? b. An F1 cat mates with a stray cat that is gray and possesses normal ears. What phenotypes and proportions of progeny are expected from this cross?arrow_forwardThe B allele confers black coat color and the b allele brown coat color in Labrador dogs. When another gene, E, is inherited, the coat is golden no matter what the B phenotype is. A dog of genotype ee expresses the black phenotype. What unusual phenomenon is at work in this disorder?arrow_forward
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