The barometric pressure at the sea level is 760mmHg. The pressure of the pressure cooker is 1.75 atm. The normal boiling point temperature difference between the boiling water in an open pot and in pressure cooker is to be determined. The heat of vaporization of water is ΔH vap =40.7kJ/mol. Concept introduction: The Clausius − Clapeyron equation is as follows: ln P 1 P 2 = − Δ H v a p R ( 1 T 1 − 1 T 2 ) Here, P 1 and P 2 = vapor pressure T 1 and T 2 = Temperature R = gas constant ΔH vap = heat of vaporization The boiling point temperature difference is - Δ T b = T 2 − T 1

Question

b) Certain cyclic compounds are known to be conformationally similar to carbohydrates, although they are not themselves carbohydrates. One example is Compound C shown below, which could be imagined as adopting four possible conformations. In reality, however, only one of these is particularly stable. Circle the conformation you expect to be the most stable, and provide an explanation to justify your choice. For your explanation to be both convincing and correct, it must contain not only words, but also "cartoon" orbital drawings contrasting the four structures. Compound C Possible conformations (circle one): Дет

Answer 1

Question

Chapter 9, Problem 12QAP

Interpretation Introduction

Interpretation:

The barometric pressure at the sea level is 760mmHg. The pressure of the pressure cooker is 1.75 atm. The normal boiling point temperature difference between the boiling water in an open pot and in pressure cooker is to be determined. The heat of vaporization of water is ΔH_vap =40.7kJ/mol.

Concept introduction:

The Clausius − Clapeyron equation is as follows:

lnP1P2=−ΔHvapR(1T1−1T2)

Here,

P₁ and P₂ = vapor pressure

T₁ and T₂ = Temperature

R = gas constant

ΔH_vap = heat of vaporization

The boiling point temperature difference is -

ΔTb=T2−T1

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