Residential Construction Academy: House Wiring (MindTap Course List)
5th Edition
ISBN: 9781337402415
Author: Gregory W Fletcher
Publisher: Cengage Learning
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Question
Chapter 9, Problem 10RQ
To determine
The sheathing of a ROMEX cable must extend atleast ___ inches
The ROMEX cable must also be secured no more than ___ inches
The NEC section that covers this wiring situation
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Chapter 9 Solutions
Residential Construction Academy: House Wiring (MindTap Course List)
Ch. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQCh. 9 - The minimum amount of free conductor required at...Ch. 9 - Prob. 5RQCh. 9 - Describe how an insulated grounded conduct or...Ch. 9 - Describe how a white Insulated conductor in a...Ch. 9 - Prob. 8RQCh. 9 - Describe how a conductor that is larger than 6 AWG...Ch. 9 - Prob. 10RQ
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- Describe how an electrician can tell Type AC and Type MC cable apart. (Objective 2-5)arrow_forwardAlthough it is not a specific requirement, most electricians feel that the best place to start a cable run for a branch circuit is at the service panel or subpanel. Explain why this is so. (Objective 11-3)arrow_forwardDescribe how a white Insulated conductor in a cable assembly is reidentified as an ungrounded hot conductor. Name the NEC section that covers this wiring situation. (Objective 9-4)arrow_forward
- If Type SER service entrance cable is used by an electrician to feed a subpanel from a main panel, the cable must be secured within _________of the panel enclosures and at Intervals not exceeding___________. Name the NEC section that states this requirement. (Objective 8-7)arrow_forwardThe minimum amount of free conductor required at an electrical box used in residential wiring for termination purposes is______________ inches. As long as the box has no dimension Larger than 8 Inches (200 mm), there must be at Least ______ inches of free conductor extending out from the box opening. Name the NEC section that covers this wiring practice. (Objective 9-3)arrow_forwardwo.t 2-22 mm (n.) 2-22mm (d,) 3-22mm (f) 12m- 23cm 8cm w 8.1 38 cm. P.L 40cm بسته 09- cm 2.6 m 23-22mm (2) -1.22mm (h) 1-22mm) -1-37m 10mm STPS. @12mm c/c -21mx18m 2.1m L38 cm 25 mm CLEAR. COVER 3-22 mm (c) -6-22 mm (d) -30 cm -6-22mm (c) 38 cm SECTION-1-1 10 mm 105 -2-22m. -2-22 mm STRAIGHT 2 IX -3-22 mm (f) PLAN OF 38 cm x 25cm. COLN. 25-22mm (4.h. i) -10 mm STPS @25cm -5.5m BINDER 23 cm 3-22 mm (c) 1-22 mm. (8) 10mm STIRRUPS- -22 mm @9 cm c/c (0) -22 mm @ 9cm c/c (b) -20 NOS. RODS (LONG SIDE) 17 NOS RODS (SHORT SIDE) 2 -1.37m- -/4-18mm STR 12 cmc/c -5-22 mm (disf) -4-22mm (h. i) 125 cm SECTION 2-2 -50mm CLEAR COVER -8 cm LEAN CONC. (1:4:8)novations 38 -Prepare a complete schedule of bars of the portal frame as shown in the 4-15. Assume weight of 22mbar-2-98 kg/rm and 10mm bar-0.62 kg/rm. Twar 469arrow_forward
- AB- 1. Find the forces acting on cach member: (Round off your answers to 2 decimal places) AC- BC- BD- CD- CE- DE- OF- EF- 104 KN EG- kN 2 2 KN KN KN 3 3 3 200 kN KN Tor C Tor C) Tor C (Tor C (Tor C) (Tor C) (Tor C) (Tor C) IT or C) (Tor) R₂ 15marrow_forwardGiven - Length of Cable PQ -25m Horizental distonce between Pa=20 m N Jom - Jo m Te Ta 8 53-13 53-13 36.8 12.5m 36-870 150KN Zet tension in cable PR and a R be Tp and l8 mespectivily Now in A P&R, Ps E RQ - 12'5 m' ニ PR = L PRS = ESR = sint( ) =53.13° 12.5 VSing lami's, theomem ,- Tp Sin (90+36.87) 150 Si'n(53.13+53.13 Sin(go+36'87) 150 xsin(90+36-87) Sin (53-13 + 5313). Tp - 124.98 KN Now we gst, the tension m the cable due to the applied load is > 125 KN い oitan of 2 12:5marrow_forwardExplain the difference between new-work and old-work electrical boxes. (Objective 10-1)arrow_forward
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