Residential Construction Academy: House Wiring (MindTap Course List)
5th Edition
ISBN: 9781337402415
Author: Gregory W Fletcher
Publisher: Cengage Learning
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Chapter 9, Problem 3RQ
To determine
The distance from the hole edge to the stud’s face and the thickness of the metal plate for protection of the cable.
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Students have asked these similar questions
The connection consists of a plate connected by a five 25-mm diameter rivets. It carries a load P=120 kN.
The maximum design force for a rivet in the
following bracket connection, if spacing
between adjacent rivets is 150 mm, is-
150 mm
150 mm
22
(a) 150 kN
(c) 200 kN
150 150
mm
mm
Column
7
160 mm
(Not to scale)
450 kN
(b) 175 kN
(d) 212.5 kN
Determine the net critical width of the riveted connection shown. Plate thickness is 25mm, and rivet diameter is 20 mm. Assume that the rivet hole is 3 mm larger than the rivet diameter.
Chapter 9 Solutions
Residential Construction Academy: House Wiring (MindTap Course List)
Ch. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQCh. 9 - The minimum amount of free conductor required at...Ch. 9 - Prob. 5RQCh. 9 - Describe how an insulated grounded conduct or...Ch. 9 - Describe how a white Insulated conductor in a...Ch. 9 - Prob. 8RQCh. 9 - Describe how a conductor that is larger than 6 AWG...Ch. 9 - Prob. 10RQ
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- 130% v - + 7 Annotate T| Edit Trial expired Unlock Full Version Q- X ENGR 263 A A A 6.12 A steel guy cable hangs vertically to support a roof system at the lower end of the cable. The 240-ft-long wire has a net cross section area of 0.75 in² and weighs 1.50 lb/ft. Ten- sile stress in the cable must not exceed 20 000 lb/in?. (a) Determine the maximum tensile stress that develops in the cable due to its own weight. (b) Determine the maximum load that can be carried at the lower end of the cable with- out exceeding the maximum specified tensile stress.arrow_forwardProblem 17. The welded connection shown in the figure uses electrodes E70XX. The nominal weld strength of the connection is: a 184.40 kN b 245.87 kN c 430.27 kN d 485.59 kN 18. For the connection shown in problem 17, the LRFD design strength is: a 322.70 kN b 364.19 kN c 387.24 kN d 437.03 kN 19. For the connection shown in problem 17, the ASD al strength is: a 215.14 kN b 242.80 kN c 322.70 kN d 387.24 kNarrow_forwardCalculate and check the design strength of the connection shown below. Is the connection adequate for carrying the factored load of 65 kips. -3/8 in. А36 5 x % 125 АЗ6 2.50 65 k 1.25 % in, bolts 1.25 2.50 1.25arrow_forward
- Q#4: A) Illustrate the bond beam in your own words. Also write few lines about the diaphragm and shear walls in your own words. (CLO-1) (PLO-1)arrow_forwardDetermine the spacing, in mm, of rivets on the steel platearrow_forwardTopic:Bolted Steel Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A channel shown is attached to a 12 mm gusset plate with 9-22 mm diameter A 325 bolts as shown. Use LRFD. Fnv = 300 MPa Fu = 400 MPa Fy = 248 MPa Ag = 3354 mm2 Question: Determine the capacity of the channel based on the bearing strength of the connection.arrow_forward
- 5. A uniform circular shaft, 750 mm long, carries 2 pulleys. The pulley on the left is 250 mm from the left end and weights 2000 N. The pulley on the right is 500 mm from the left end and weighs 1274 N. The right pulley experiences a pull of 14,142 N vertically downwards. The shaft transmits a torque of 3 kN-m between the pulleys. Assume Km and Ks equal to 1.5 and allowable shear stress of 70 MPa. Determine (a) the maximum bending moment in N-m and (b) the required diameter of the shaft in mm.arrow_forwardP= 430N M= 860 N•m M 1 m 1 m B m find: Cx & Cy P -2 m- Show Transcribed Text Aarrow_forwardTopic:Bolted Steel Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A channel shown is attached to a 12 mm gusset plate with 9-22 mm diameter A 325 bolts as shown. Use LRFD. Fnv = 300 MPa Fu = 400 MPa Fy = 248 MPa Ag = 3354 mm2 Question: a) Determine the capacity of the channel based on the gross area and effective net are. U = 0.60 b) Determine the capacity of the channel based on the shearing capacity of the bolts.arrow_forward
- Problem 5: The lap connection shown consists of a PL1/2"X3" plate connected to a ½ in gusset plate with ¼" longitudinal fillet welds as indicated. The plates are A36 steel and the electrodes are E70XX. Calculate the length L (in) of the connection to develop the full capacity of the plate. Hint: The full capacity of the plate will depend on the governing strength of the tension member. Neglect block shear. Use ASD 6" x 1/2" P [ T L 1/4 1/4 E70 - 13²x P 3" x 1/2"arrow_forwardDetermine the adequacy of the clip angle connection shown. The allowable stresses are 100mpa for shearing. 220 Mpa for bearing, and 140 Mpa for tension for the seat angle and the rivets.figure belowarrow_forwardPlease answer as soon as possiblearrow_forward
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