Chapter 9, Problem 101A

Interpretation Introduction

(a)

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be determined.

${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(aq\right)+3\text{RbOH}\left(aq\right)\to 3{\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{Rb}}_{\text{3}}{\text{PO}}_4\left(aq\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula. Net ionic equation eliminates all ions which are shared by both sides.

Answer to Problem 101A

For given equation, ionic equation is as follows:

$3{\text{H}}^{\text{+}}\left(aq\right)+{\text{PO}}_4{}^{3-}\left(aq\right){\text{+3Rb}}^{\text{+}}\left(aq\right){\text{+3OH}}^{-}\left(aq\right)\to 3{\text{H}}_{\text{2}}\text{O}\left(l\right)+3{\text{Rb}}^{+}\left(aq\right)+{\text{PO}}_4{}^{3-}\left(aq\right)$

After eliminates all ions that are shared by both sides net ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right){\text{+OH}}^{-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)$

Explanation of Solution

The given equation is as follows:

${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(aq\right)+3\text{RbOH}\left(aq\right)\to 3{\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{Rb}}_{\text{3}}{\text{PO}}_4\left(aq\right)$

For the above equation ionic equation is as follows:

$3{\text{H}}^{\text{+}}\left(aq\right)+{\text{PO}}_4{}^{3-}\left(aq\right){\text{+3Rb}}^{\text{+}}\left(aq\right){\text{+3OH}}^{-}\left(aq\right)\to 3{\text{H}}_{\text{2}}\text{O}\left(l\right)+3{\text{Rb}}^{+}\left(aq\right)+{\text{PO}}_4{}^{3-}\left(aq\right)$

After eliminates all ions that are shared by both sides net ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right){\text{+OH}}^{-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)$

(b)

Interpretation Introduction

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be determined.

$\text{HCl}\left(aq\right)+{\text{NH}}_{\text{4}}\text{OH}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{NH}}_{\text{4}}\text{Cl}\left(aq\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula. Net ionic equation eliminates all ions which are shared by both sides.

Explanation of Solution

The given equation is as follows:

$\text{HCl}\left(aq\right)+{\text{NH}}_{\text{4}}\text{OH}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{NH}}_{\text{4}}\text{Cl}\left(aq\right)$

For the above equation ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right)+{\text{Cl}}^{-}\left(aq\right){\text{+NH}}_{\text{4}}{}^{\text{+}}\left(aq\right){\text{+OH}}^{-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{NH}}_{\text{4}}{}^{+}\left(aq\right)+{\text{Cl}}^{-}\left(aq\right)$

Eliminates all ions that are shared by both sides net ionic equation and change the carbonate group to carbon dioxide leaves out an oxygen atom in the product. In the reactants hydrogen must appear. Net ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right){\text{+OH}}^{-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)$

(c)

Interpretation Introduction

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be written.

$2\text{HI}\left(aq\right)+{\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}\text{S}\left(aq\right)\to {\text{H}}_{\text{2}}\text{S}\left(g\right)+2{\text{NH}}_{\text{4}}\text{I}\left(aq\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula. Net ionic equation eliminates all ions which are shared by both sides.

Answer to Problem 101A

For given equation ionic equation is as follows:

${\text{2H}}^{\text{+}}\left(aq\right)+2{\text{I}}^{-}\left(aq\right){\text{+2NH}}_{\text{4}}{}^{\text{+}}\left(aq\right){\text{+S}}^{2-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{S}\left(g\right)+2{\text{NH}}^{+}{}_4\left(aq\right)+2{\text{I}}^{-}\left(aq\right)$

After eliminates all ions that are shared by both sides net ionic equation is as follows:

${\text{2H}}^{\text{+}}\left(aq\right){\text{+S}}^{2-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{S}\left(g\right)$

Explanation of Solution

The given equation is as follows:

$2\text{HI}+{\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}\text{S}\left(aq\right)\to {\text{H}}_{\text{2}}\text{S}\left(g\right)+2{\text{NH}}_{\text{4}}\text{I}\left(aq\right)$

For the above equation ionic equation is as follows:

${\text{2H}}^{\text{+}}\left(aq\right)+2{\text{I}}^{-}\left(aq\right){\text{+2NH}}_{\text{4}}{}^{\text{+}}\left(aq\right){\text{+S}}^{2-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{S}\left(g\right)+2{\text{NH}}^{+}{}_4\left(aq\right)+2{\text{I}}^{-}\left(aq\right)$

Eliminates all ions that are shared by both sides net ionic equation and change the carbonate group to carbon dioxide leaves out an oxygen atom in the product. In the reactants hydrogen must appear. Net ionic equation is as follows:

${\text{2H}}^{\text{+}}\left(aq\right){\text{+S}}^{2-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{S}\left(g\right)$

(d)

Interpretation Introduction

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be determined.

${\text{HNO}}_{\text{3}}\left(aq\right)+\text{KCN}\left(aq\right)\to \text{HCN}\left(g\right)+{\text{KNO}}_{\text{3}}\left(aq\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula. Net ionic equation eliminates all ions which are shared by both sides.

Answer to Problem 101A

For given equation ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right)+{\text{NO}}_3{}^{-}\left(aq\right){\text{+K}}^{\text{+}}\left(aq\right){\text{+CN}}^{-}\left(aq\right)\to \text{HCN}\left(g\right)+{\text{K}}^{\text{+}}\left(aq\right){\text{+NO}}_{\text{3}}{}^{-}\left(aq\right)$

After eliminates all ions that are shared by both sides net ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right){\text{+CN}}^{-}\left(aq\right)\to \text{HCN}\left(g\right)$

Explanation of Solution

The given equation is as follows:

${\text{HNO}}_{\text{3}}\left(aq\right)+\text{KCN}\left(aq\right)\to \text{HCN}\left(g\right)+{\text{KNO}}_{\text{3}}\left(aq\right)$

For the above equation ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right)+{\text{NO}}_3{}^{-}\left(aq\right){\text{+K}}^{\text{+}}\left(aq\right){\text{+CN}}^{-}\left(aq\right)\to \text{HCN}\left(g\right)+{\text{K}}^{\text{+}}\left(aq\right){\text{+NO}}_{\text{3}}{}^{-}\left(aq\right)$

Eliminates all ions that are shared by both sides net ionic equation and change the carbonate group to carbon dioxide leaves out an oxygen atom in the product. In the reactants hydrogen must appear. Net ionic equation is as follows:

${\text{H}}^{\text{+}}\left(aq\right){\text{+CN}}^{-}\left(aq\right)\to \text{HCN}\left(g\right)$