(a)
Interpretation:
The element that will replace the other in a reaction among tin and sodium needs to be determined.
Concept introduction:
The reactivity series of metals is as follows:
Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold
Answer to Problem 80A
Sodium will replace tin in a reaction.
Explanation of Solution
The reactivity series of metals is as follows:
Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold
The metal higher on the series is the most active and the metal lower on the series is less active.
Therefore, sodium will replace tin in a reaction.
(b)
Interpretation:
The element that will replace the other in a reaction among fluorine and iodine needs to be determined.
Concept introduction:
The activity series of halogens is given as follows:
Fluorine > Chlorine > Bromine > iodine
(b)
Answer to Problem 80A
Fluorine will replace iodine.
Explanation of Solution
The activity series of halogens is given as follows:
Fluorine > Chlorine > Bromine > iodine
The halogen higher on the series is the most active and the halogen lower on the series is less active.
Therefore, fluorine will replace iodine.
(c)
Interpretation:
The element that will replace the other in a reaction among lead and silver needs to be determined.
Concept introduction:
The reactivity series of metals is as follows:
Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold
(c)
Answer to Problem 80A
Lead will replace Silver
Explanation of Solution
The reactivity series of metals is as follows:
Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold
The metal higher on the series is the most active and the metal lower on the series is less active.
Therefore, Lead will replace Silver.
(d)
Interpretation:
The element that will replace the other in a reaction among copper and nickel needs to be determined.
Concept introduction:
The reactivity series of metals is as follows:
Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold
(d)
Answer to Problem 80A
Nickel will replace Copper.
Explanation of Solution
The reactivity series of metals is as follows:
Lithium > Rubidium > Potassium > Calcium > Sodium > Magnesium > Aluminium > Manganese > Zinc > Iron > Nickel > Tin > Lead > Copper > Silver > Platinum > Gold
The metal higher on the series is the most active and the metal lower on the series is less active.
Therefore, Nickel will replace Copper.
Chapter 9 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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