
To describe and correct:
The error in the graph of the given inequality.

Answer to Problem 13E
The correct shaded region will be the other side of the boundary line.
Explanation of Solution
Given:
An inequality and its graph:
Calculation:
Upon looking at our given inequality, we can see that it has a greater than or equal to sign. So the boundary line of our given inequality will be a solid line and the points on boundary line will be solution of the inequality.
To shade in the correct region, we will test point (0,0) in our given inequality as:
Since the point satisfies our inequality, so we will shade in the region that includes point (0,0).
We can see from graph of given inequality that the shaded region doesn’t include point (0,0). The correct graph of our given inequality would look like:
Chapter 8 Solutions
ELEMENTARY+INTERMEDIATE ALGEBRA
Additional Math Textbook Solutions
Elementary Statistics: Picturing the World (7th Edition)
Calculus: Early Transcendentals (2nd Edition)
Calculus: Early Transcendentals (2nd Edition)
Precalculus
Basic Business Statistics, Student Value Edition
A First Course in Probability (10th Edition)
- Solve the following systems of equations and show all work.y = x2 + 3y = x + 5 Please type out answerarrow_forwardSolve the following system of equations. Show all work and solutions.y = 2x2 + 6x + 1y = −4x2 + 1 Please type out answerarrow_forwardDalia buys 20 collectible gems per month. Grace sells 10 gems from her collection of 120 each month. When will Dalia have more gems than Grace? Show your work. Dear Student If You Face any issue let me know i will solve your all doubt. I will provide solution again in more detail systematic and organized way. I would also like my last 3 questions credited to mearrow_forward
- Dalia buys 20 collectible gems per month. Grace sells 10 gems from her collection of 120 each month. When will Dalia have more gems than Grace? Show your work.arrow_forwardSolve the following system of equations. Show all work and solutions.y = 2x2 + 6x + 1y = −4x2 + 1arrow_forwardSolve the following systems of equations and show all work.y = x2 + 3y = x + 5arrow_forward
- Write an equation for the function shown. You may assume all intercepts and asymptotes are on integers. The blue dashed lines are the asymptotes. 10 9- 8- 7 6 5 4- 3- 2 4 5 15-14-13-12-11-10 -9 -8 -7 -6 -5 -4 -3 -2 1 1 2 3 -1 -2 -3 -4 1 -5 -6- -7 -8- -9 -10+ 60 7 8 9 10 11 12 13 14 15arrow_forwardUse the graph of the polynomial function of degree 5 to identify zeros and multiplicity. Order your zeros from least to greatest. -6 3 6+ 5 4 3 2 1 2 -1 -2 -3 -4 -5 3 4 6 Zero at with multiplicity Zero at with multiplicity Zero at with multiplicityarrow_forwardUse the graph to identify zeros and multiplicity. Order your zeros from least to greatest. 6 5 4 -6-5-4-3-2 3 21 2 1 2 4 5 ૪ 345 Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity པ་arrow_forward
- Use the graph to write the formula for a polynomial function of least degree. -5 + 4 3 ♡ 2 12 1 f(x) -1 -1 f(x) 2 3. + -3 12 -5+ + xarrow_forwardUse the graph to identify zeros and multiplicity. Order your zeros from least to greatest. 6 -6-5-4-3-2-1 -1 -2 3 -4 4 5 6 a Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity Zero at with multiplicityarrow_forwardUse the graph to write the formula for a polynomial function of least degree. 5 4 3 -5 -x 1 f(x) -5 -4 -1 1 2 3 4 -1 -2 -3 -4 -5 f(x) =arrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education





