Explanation Write the formula of interpolation method of two variables. y 2 = ( x 2 − x 1 ) ( y 3 − y 1 ) ( x 3 − x 1 ) + y 1 (I) Here, the variables denoted by x and y are enthalpy and entropy. Write the expression for the decrease in the exergy of the steam during the throttling process. ψ 1 − ψ 2 = − [ T 0 ( s 1 − s 2 ) ] = T 0 ( s 2 − s 1 ) (II) Here, thermodynamic temperature of the environment is T 0 . Conclusion: From Table A-6E, “Superheated water”, select the initial enthalpy ( h 1 ) and initial entropy ( s 1 ) at the pressure of 7 MPa and temperature of 500°C as 3 , 411.4 kJ / kg and 6.8000 kJ / kg ⋅ K respectively. Refer to Table A-6, “superheated water”, for the pressure ( P 2 ) of 1 MPa and final enthalpy ( h 2 ) of 3 , 411.4 kJ / kg to obtain the following properties using interpolation method. Pressure MPa Enthalpy kJ / kg Entropy kJ / kg ⋅ K 1 3 , 264.5 7.4670 1 3 , 411.4 ? 1 3 , 479.1 7.7642 Here, final entropy of steam is s 2 , final pressure is P 2 and final enthalpy is h 2 . Substitute 3 , 411.4 kJ / kg for x 2 , 3 , 264.5 kJ / kg for x 1 , 3 , 479

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Author: CENGEL

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Chapter 8.8, Problem 59P

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The decrease in the exergy of the steam during the throttling process

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Chapter 8.8, Problem 58P

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EBK THERMODYNAMICS: AN ENGINEERING APPR

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