Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
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Chapter 8.5, Problem 29PSC
To determine

To show that the given information is impossible.

Expert Solution & Answer
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Answer to Problem 29PSC

The given information is not correct.

Explanation of Solution

Given information:

  RW bisects SRT .

  TV bisects RTS .

  RV=4,SV=5,SW=6,WT=7

Formula used:

The below theorem is used:

Angle bisector theorem states that an angle bisector of a triangle will divide the opposite side into two segments that are proportional to the other two sides of the triangle.

Calculation:

  Geometry For Enjoyment And Challenge, Chapter 8.5, Problem 29PSC

Using Angle Bisector Theorem, for R we get

  SWWT=RSRT67=9RT6RT=63RT=10.5

Now, for the T

  RVVS=RTTS45=RT135RT=52RT=10.4

But RT cannot have two different lengths, therefore the given information is not correct.

Chapter 8 Solutions

Geometry For Enjoyment And Challenge

Ch. 8.1 - Prob. 11PSACh. 8.1 - Prob. 12PSACh. 8.1 - Prob. 13PSACh. 8.1 - Prob. 14PSACh. 8.1 - Prob. 15PSACh. 8.1 - Prob. 16PSBCh. 8.1 - Prob. 17PSBCh. 8.1 - Prob. 18PSBCh. 8.1 - Prob. 19PSBCh. 8.1 - Prob. 20PSBCh. 8.1 - Prob. 21PSBCh. 8.1 - Prob. 22PSBCh. 8.1 - Prob. 23PSCCh. 8.1 - Prob. 24PSCCh. 8.1 - Prob. 25PSCCh. 8.1 - Prob. 26PSCCh. 8.1 - Prob. 27PSDCh. 8.2 - Prob. 1PSACh. 8.2 - Prob. 2PSACh. 8.2 - Prob. 3PSACh. 8.2 - Prob. 4PSACh. 8.2 - Prob. 5PSACh. 8.2 - Prob. 6PSACh. 8.2 - Prob. 7PSACh. 8.2 - Prob. 8PSACh. 8.2 - Prob. 9PSBCh. 8.2 - Prob. 10PSBCh. 8.2 - Prob. 11PSBCh. 8.2 - Prob. 12PSBCh. 8.2 - Prob. 13PSBCh. 8.2 - Prob. 14PSBCh. 8.2 - Prob. 15PSBCh. 8.2 - Prob. 16PSBCh. 8.2 - Prob. 17PSBCh. 8.2 - Prob. 18PSCCh. 8.2 - Prob. 19PSCCh. 8.3 - Prob. 1PSACh. 8.3 - Prob. 2PSACh. 8.3 - Prob. 3PSACh. 8.3 - Prob. 4PSACh. 8.3 - Prob. 5PSACh. 8.3 - Prob. 6PSACh. 8.3 - Prob. 7PSACh. 8.3 - Prob. 8PSACh. 8.3 - Prob. 9PSACh. 8.3 - Prob. 10PSACh. 8.3 - Prob. 11PSACh. 8.3 - Prob. 12PSBCh. 8.3 - Prob. 13PSBCh. 8.3 - Prob. 14PSBCh. 8.3 - Prob. 15PSBCh. 8.3 - Prob. 16PSBCh. 8.3 - Prob. 17PSBCh. 8.3 - Prob. 18PSBCh. 8.3 - Prob. 19PSBCh. 8.3 - Prob. 20PSBCh. 8.3 - Prob. 21PSCCh. 8.3 - Prob. 22PSCCh. 8.4 - Prob. 1PSACh. 8.4 - Prob. 2PSACh. 8.4 - Prob. 3PSACh. 8.4 - Prob. 4PSACh. 8.4 - Prob. 5PSACh. 8.4 - Prob. 6PSACh. 8.4 - Prob. 7PSACh. 8.4 - Prob. 8PSACh. 8.4 - Prob. 9PSACh. 8.4 - Prob. 10PSACh. 8.4 - Prob. 11PSACh. 8.4 - Prob. 12PSBCh. 8.4 - Prob. 13PSBCh. 8.4 - Prob. 14PSBCh. 8.4 - Prob. 15PSBCh. 8.4 - Prob. 16PSBCh. 8.4 - Prob. 17PSBCh. 8.4 - Prob. 18PSBCh. 8.4 - Prob. 19PSBCh. 8.4 - Prob. 20PSBCh. 8.4 - Prob. 21PSBCh. 8.4 - Prob. 22PSCCh. 8.4 - Prob. 23PSCCh. 8.4 - Prob. 24PSCCh. 8.5 - Prob. 1PSACh. 8.5 - Prob. 2PSACh. 8.5 - Prob. 3PSACh. 8.5 - Prob. 4PSACh. 8.5 - Prob. 5PSACh. 8.5 - Prob. 6PSACh. 8.5 - Prob. 7PSACh. 8.5 - Prob. 8PSACh. 8.5 - Prob. 9PSACh. 8.5 - Prob. 10PSACh. 8.5 - Prob. 11PSACh. 8.5 - Prob. 12PSACh. 8.5 - Prob. 13PSACh. 8.5 - Prob. 14PSACh. 8.5 - Prob. 15PSACh. 8.5 - Prob. 16PSBCh. 8.5 - Prob. 17PSBCh. 8.5 - Prob. 18PSBCh. 8.5 - Prob. 19PSBCh. 8.5 - Prob. 20PSBCh. 8.5 - Prob. 21PSBCh. 8.5 - Prob. 22PSBCh. 8.5 - Prob. 23PSBCh. 8.5 - Prob. 24PSBCh. 8.5 - Prob. 25PSBCh. 8.5 - Prob. 26PSCCh. 8.5 - Prob. 27PSCCh. 8.5 - Prob. 28PSCCh. 8.5 - Prob. 29PSCCh. 8.5 - Prob. 30PSCCh. 8 - Prob. 1RPCh. 8 - Prob. 2RPCh. 8 - Prob. 3RPCh. 8 - Prob. 4RPCh. 8 - Prob. 5RPCh. 8 - Prob. 6RPCh. 8 - Prob. 7RPCh. 8 - Prob. 8RPCh. 8 - Prob. 9RPCh. 8 - Prob. 10RPCh. 8 - Prob. 11RPCh. 8 - Prob. 12RPCh. 8 - Prob. 13RPCh. 8 - Prob. 14RPCh. 8 - Prob. 15RPCh. 8 - Prob. 16RPCh. 8 - Prob. 17RPCh. 8 - Prob. 18RPCh. 8 - Prob. 19RPCh. 8 - Prob. 20RPCh. 8 - Prob. 21RPCh. 8 - Prob. 22RPCh. 8 - Prob. 23RPCh. 8 - Prob. 24RPCh. 8 - Prob. 25RPCh. 8 - Prob. 26RPCh. 8 - Prob. 27RPCh. 8 - Prob. 28RPCh. 8 - Prob. 29RPCh. 8 - Prob. 30RPCh. 8 - Prob. 31RPCh. 8 - Prob. 32RPCh. 8 - Prob. 33RPCh. 8 - Prob. 34RPCh. 8 - Prob. 35RP
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