Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 8.4, Problem 5PSA
To determine

To show that product of two sides are equal.

Expert Solution & Answer
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Answer to Problem 5PSA

  Product of NO and RT is equal to product of RS and NP.

Explanation of Solution

Given information:

  ΔNOP~ ΔRST

Formula used:

The below properties are used:

Corresponding sides of similar triangles are proportional.

Means extremes product theorem:

If a product of a pair of not zero numbers is equal to the product of another pair of not zero numbers, then either pair of numbers be made the extremes, and the other pair the means, of proportion.

Proof:

  Geometry For Enjoyment And Challenge, Chapter 8.4, Problem 5PSA

It is given that,

  ΔNOP~ ΔRST

Corresponding sides of similar triangles are proportional.

  NO/RS = NP/RT

Applying means extremes product theorem, we get

  NO . RT = RS . NP

Chapter 8 Solutions

Geometry For Enjoyment And Challenge

Ch. 8.1 - Prob. 11PSACh. 8.1 - Prob. 12PSACh. 8.1 - Prob. 13PSACh. 8.1 - Prob. 14PSACh. 8.1 - Prob. 15PSACh. 8.1 - Prob. 16PSBCh. 8.1 - Prob. 17PSBCh. 8.1 - Prob. 18PSBCh. 8.1 - Prob. 19PSBCh. 8.1 - Prob. 20PSBCh. 8.1 - Prob. 21PSBCh. 8.1 - Prob. 22PSBCh. 8.1 - Prob. 23PSCCh. 8.1 - Prob. 24PSCCh. 8.1 - Prob. 25PSCCh. 8.1 - Prob. 26PSCCh. 8.1 - Prob. 27PSDCh. 8.2 - Prob. 1PSACh. 8.2 - Prob. 2PSACh. 8.2 - Prob. 3PSACh. 8.2 - Prob. 4PSACh. 8.2 - Prob. 5PSACh. 8.2 - Prob. 6PSACh. 8.2 - Prob. 7PSACh. 8.2 - Prob. 8PSACh. 8.2 - Prob. 9PSBCh. 8.2 - Prob. 10PSBCh. 8.2 - Prob. 11PSBCh. 8.2 - Prob. 12PSBCh. 8.2 - Prob. 13PSBCh. 8.2 - Prob. 14PSBCh. 8.2 - Prob. 15PSBCh. 8.2 - Prob. 16PSBCh. 8.2 - Prob. 17PSBCh. 8.2 - Prob. 18PSCCh. 8.2 - Prob. 19PSCCh. 8.3 - Prob. 1PSACh. 8.3 - Prob. 2PSACh. 8.3 - Prob. 3PSACh. 8.3 - Prob. 4PSACh. 8.3 - Prob. 5PSACh. 8.3 - Prob. 6PSACh. 8.3 - Prob. 7PSACh. 8.3 - Prob. 8PSACh. 8.3 - Prob. 9PSACh. 8.3 - Prob. 10PSACh. 8.3 - Prob. 11PSACh. 8.3 - Prob. 12PSBCh. 8.3 - Prob. 13PSBCh. 8.3 - Prob. 14PSBCh. 8.3 - Prob. 15PSBCh. 8.3 - Prob. 16PSBCh. 8.3 - Prob. 17PSBCh. 8.3 - Prob. 18PSBCh. 8.3 - Prob. 19PSBCh. 8.3 - Prob. 20PSBCh. 8.3 - Prob. 21PSCCh. 8.3 - Prob. 22PSCCh. 8.4 - Prob. 1PSACh. 8.4 - Prob. 2PSACh. 8.4 - Prob. 3PSACh. 8.4 - Prob. 4PSACh. 8.4 - Prob. 5PSACh. 8.4 - Prob. 6PSACh. 8.4 - Prob. 7PSACh. 8.4 - Prob. 8PSACh. 8.4 - Prob. 9PSACh. 8.4 - Prob. 10PSACh. 8.4 - Prob. 11PSACh. 8.4 - Prob. 12PSBCh. 8.4 - Prob. 13PSBCh. 8.4 - Prob. 14PSBCh. 8.4 - Prob. 15PSBCh. 8.4 - Prob. 16PSBCh. 8.4 - Prob. 17PSBCh. 8.4 - Prob. 18PSBCh. 8.4 - Prob. 19PSBCh. 8.4 - Prob. 20PSBCh. 8.4 - Prob. 21PSBCh. 8.4 - Prob. 22PSCCh. 8.4 - Prob. 23PSCCh. 8.4 - Prob. 24PSCCh. 8.5 - Prob. 1PSACh. 8.5 - Prob. 2PSACh. 8.5 - Prob. 3PSACh. 8.5 - Prob. 4PSACh. 8.5 - Prob. 5PSACh. 8.5 - Prob. 6PSACh. 8.5 - Prob. 7PSACh. 8.5 - Prob. 8PSACh. 8.5 - Prob. 9PSACh. 8.5 - Prob. 10PSACh. 8.5 - Prob. 11PSACh. 8.5 - Prob. 12PSACh. 8.5 - Prob. 13PSACh. 8.5 - Prob. 14PSACh. 8.5 - Prob. 15PSACh. 8.5 - Prob. 16PSBCh. 8.5 - Prob. 17PSBCh. 8.5 - Prob. 18PSBCh. 8.5 - Prob. 19PSBCh. 8.5 - Prob. 20PSBCh. 8.5 - Prob. 21PSBCh. 8.5 - Prob. 22PSBCh. 8.5 - Prob. 23PSBCh. 8.5 - Prob. 24PSBCh. 8.5 - Prob. 25PSBCh. 8.5 - Prob. 26PSCCh. 8.5 - Prob. 27PSCCh. 8.5 - Prob. 28PSCCh. 8.5 - Prob. 29PSCCh. 8.5 - Prob. 30PSCCh. 8 - Prob. 1RPCh. 8 - Prob. 2RPCh. 8 - Prob. 3RPCh. 8 - Prob. 4RPCh. 8 - Prob. 5RPCh. 8 - Prob. 6RPCh. 8 - Prob. 7RPCh. 8 - Prob. 8RPCh. 8 - Prob. 9RPCh. 8 - Prob. 10RPCh. 8 - Prob. 11RPCh. 8 - Prob. 12RPCh. 8 - Prob. 13RPCh. 8 - Prob. 14RPCh. 8 - Prob. 15RPCh. 8 - Prob. 16RPCh. 8 - Prob. 17RPCh. 8 - Prob. 18RPCh. 8 - Prob. 19RPCh. 8 - Prob. 20RPCh. 8 - Prob. 21RPCh. 8 - Prob. 22RPCh. 8 - Prob. 23RPCh. 8 - Prob. 24RPCh. 8 - Prob. 25RPCh. 8 - Prob. 26RPCh. 8 - Prob. 27RPCh. 8 - Prob. 28RPCh. 8 - Prob. 29RPCh. 8 - Prob. 30RPCh. 8 - Prob. 31RPCh. 8 - Prob. 32RPCh. 8 - Prob. 33RPCh. 8 - Prob. 34RPCh. 8 - Prob. 35RP

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