Chapter 8.4, Problem 15PSB

To determine

Prove that $\frac{JK}{JO}=\frac{JT}{JS}$ .

Answer to Problem 15PSB

Proved $\frac{JK}{JO}=\frac{JT}{JS}$ .

Explanation of Solution

Given information:

  

  $m\left|\right|p\left|\right|rJ$ lies in $m$$KT$ lies in $p$ and $OS$ lies in $r$ .

Calculation:

It is given that, $m\left|\right|p\left|\right|rJ$ lies in $m$

  $KT$ lies in $p$ and $OS$ lies in $r$ .

  $\begin{array}{l}KT\left|\right|OSand\angle JKT=\angle JOSand\angle JTK=\angle JSO\\ soasperAAA\text{}\text{}property,\\ \Delta JKT\approx \Delta JOS\\ sothat,\\ \frac{JK}{JO}=\frac{JT}{JS}\end{array}$

Hence, proved $\frac{JK}{JO}=\frac{JT}{JS}$ .