Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 8, Problem 16RP
To determine

To calculate: The length of EO and EK segment.

Expert Solution & Answer
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Answer to Problem 16RP

The length of segments: EO = 1.2 units and EK = 9 units

Explanation of Solution

Given information:

The segments, EFGOHMJK

The length of segments: FG = 2, GH = 8, HJ = 5, EM = 6

Formula used:

Ratio of lengths of corresponding segments are equivalent

Calculation:

  EOEM=FGFH=FGFG+GHEO=EM×FGFG+GHEO=6×22+8=6×210EO=1.2 units

Again, we have

  EKEO=FJFG=FG+GH+HJFGEK=EO×FG+GH+HJFGEK=1.2×2+8+52=1.2×152EK=1.2×7.5=9 units

Chapter 8 Solutions

Geometry For Enjoyment And Challenge

Ch. 8.1 - Prob. 11PSACh. 8.1 - Prob. 12PSACh. 8.1 - Prob. 13PSACh. 8.1 - Prob. 14PSACh. 8.1 - Prob. 15PSACh. 8.1 - Prob. 16PSBCh. 8.1 - Prob. 17PSBCh. 8.1 - Prob. 18PSBCh. 8.1 - Prob. 19PSBCh. 8.1 - Prob. 20PSBCh. 8.1 - Prob. 21PSBCh. 8.1 - Prob. 22PSBCh. 8.1 - Prob. 23PSCCh. 8.1 - Prob. 24PSCCh. 8.1 - Prob. 25PSCCh. 8.1 - Prob. 26PSCCh. 8.1 - Prob. 27PSDCh. 8.2 - Prob. 1PSACh. 8.2 - Prob. 2PSACh. 8.2 - Prob. 3PSACh. 8.2 - Prob. 4PSACh. 8.2 - Prob. 5PSACh. 8.2 - Prob. 6PSACh. 8.2 - Prob. 7PSACh. 8.2 - Prob. 8PSACh. 8.2 - Prob. 9PSBCh. 8.2 - Prob. 10PSBCh. 8.2 - Prob. 11PSBCh. 8.2 - Prob. 12PSBCh. 8.2 - Prob. 13PSBCh. 8.2 - Prob. 14PSBCh. 8.2 - Prob. 15PSBCh. 8.2 - Prob. 16PSBCh. 8.2 - Prob. 17PSBCh. 8.2 - Prob. 18PSCCh. 8.2 - Prob. 19PSCCh. 8.3 - Prob. 1PSACh. 8.3 - Prob. 2PSACh. 8.3 - Prob. 3PSACh. 8.3 - Prob. 4PSACh. 8.3 - Prob. 5PSACh. 8.3 - Prob. 6PSACh. 8.3 - Prob. 7PSACh. 8.3 - Prob. 8PSACh. 8.3 - Prob. 9PSACh. 8.3 - Prob. 10PSACh. 8.3 - Prob. 11PSACh. 8.3 - Prob. 12PSBCh. 8.3 - Prob. 13PSBCh. 8.3 - Prob. 14PSBCh. 8.3 - Prob. 15PSBCh. 8.3 - Prob. 16PSBCh. 8.3 - Prob. 17PSBCh. 8.3 - Prob. 18PSBCh. 8.3 - Prob. 19PSBCh. 8.3 - Prob. 20PSBCh. 8.3 - Prob. 21PSCCh. 8.3 - Prob. 22PSCCh. 8.4 - Prob. 1PSACh. 8.4 - Prob. 2PSACh. 8.4 - Prob. 3PSACh. 8.4 - Prob. 4PSACh. 8.4 - Prob. 5PSACh. 8.4 - Prob. 6PSACh. 8.4 - Prob. 7PSACh. 8.4 - Prob. 8PSACh. 8.4 - Prob. 9PSACh. 8.4 - Prob. 10PSACh. 8.4 - Prob. 11PSACh. 8.4 - Prob. 12PSBCh. 8.4 - Prob. 13PSBCh. 8.4 - Prob. 14PSBCh. 8.4 - Prob. 15PSBCh. 8.4 - Prob. 16PSBCh. 8.4 - Prob. 17PSBCh. 8.4 - Prob. 18PSBCh. 8.4 - Prob. 19PSBCh. 8.4 - Prob. 20PSBCh. 8.4 - Prob. 21PSBCh. 8.4 - Prob. 22PSCCh. 8.4 - Prob. 23PSCCh. 8.4 - Prob. 24PSCCh. 8.5 - Prob. 1PSACh. 8.5 - Prob. 2PSACh. 8.5 - Prob. 3PSACh. 8.5 - Prob. 4PSACh. 8.5 - Prob. 5PSACh. 8.5 - Prob. 6PSACh. 8.5 - Prob. 7PSACh. 8.5 - Prob. 8PSACh. 8.5 - Prob. 9PSACh. 8.5 - Prob. 10PSACh. 8.5 - Prob. 11PSACh. 8.5 - Prob. 12PSACh. 8.5 - Prob. 13PSACh. 8.5 - Prob. 14PSACh. 8.5 - Prob. 15PSACh. 8.5 - Prob. 16PSBCh. 8.5 - Prob. 17PSBCh. 8.5 - Prob. 18PSBCh. 8.5 - Prob. 19PSBCh. 8.5 - Prob. 20PSBCh. 8.5 - Prob. 21PSBCh. 8.5 - Prob. 22PSBCh. 8.5 - Prob. 23PSBCh. 8.5 - Prob. 24PSBCh. 8.5 - Prob. 25PSBCh. 8.5 - Prob. 26PSCCh. 8.5 - Prob. 27PSCCh. 8.5 - Prob. 28PSCCh. 8.5 - Prob. 29PSCCh. 8.5 - Prob. 30PSCCh. 8 - Prob. 1RPCh. 8 - Prob. 2RPCh. 8 - Prob. 3RPCh. 8 - Prob. 4RPCh. 8 - Prob. 5RPCh. 8 - Prob. 6RPCh. 8 - Prob. 7RPCh. 8 - Prob. 8RPCh. 8 - Prob. 9RPCh. 8 - Prob. 10RPCh. 8 - Prob. 11RPCh. 8 - Prob. 12RPCh. 8 - Prob. 13RPCh. 8 - Prob. 14RPCh. 8 - Prob. 15RPCh. 8 - Prob. 16RPCh. 8 - Prob. 17RPCh. 8 - Prob. 18RPCh. 8 - Prob. 19RPCh. 8 - Prob. 20RPCh. 8 - Prob. 21RPCh. 8 - Prob. 22RPCh. 8 - Prob. 23RPCh. 8 - Prob. 24RPCh. 8 - Prob. 25RPCh. 8 - Prob. 26RPCh. 8 - Prob. 27RPCh. 8 - Prob. 28RPCh. 8 - Prob. 29RPCh. 8 - Prob. 30RPCh. 8 - Prob. 31RPCh. 8 - Prob. 32RPCh. 8 - Prob. 33RPCh. 8 - Prob. 34RPCh. 8 - Prob. 35RP
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