Chapter 8.4, Problem 14MCQ

To determine

To find the product of given two polynomials.

Answer to Problem 14MCQ

  $6y^3+18y^2+6y$

Explanation of Solution

Given:

  $6y\left(y^2+3y+1\right)$

Formula used:

Distributive Law:

  $x\left(y\pm z\right)=x\cdot y\pm x\cdot z$

Calculation:

Consider the given polynomial,

  $\Rightarrow 6y\left(y^2+3y+1\right)$

  $\Rightarrow 6y\cdot y^2+6y\cdot 3y+6y\cdot 1$      [ $\because$$x\left(y\pm z\right)=x\cdot y\pm x\cdot z$ ]

  $\Rightarrow 6y^3+18y^2+6y$

Conclusion:

Therefore, product of the given polynomials is $6y^3+18y^2+6y$ .