Chapter 8.6, Problem 53HP

To determine

To determine the difference in the length of the naval rectangular flag to than of square flag.

Answer to Problem 53HP

  $(4x-12)$

Explanation of Solution

Given:

Area of square flag = $x^2-6x+9$ square feet.

Area of rectangular flag = $x^2-2x-3$ square feet.

Calculation:

Given,

Area of square flag = $x^2-6x+9$ square feet.

Area of rectangular flag = $x^2-2x-3$ square feet.

The difference in the length = Area of rectangular flag − Area of square flag

            $\begin{array}{l}=(x^2-2x-3)-(x^2-6x+9)\\ =x^2-2x-3-(x^2-6x+9)\\ =x^2-2x-3-x^2+6x-9)\\ =4x-12\end{array}$

Conclusion:

So, the difference in the length of the naval rectangular flag to that of square flag is

  $4x-12$ square feet.