Chapter 8.5, Problem 26PPS

To determine

To factor: The polynomial $24ty-18t+4y-3$

Answer to Problem 26PPS

  $\left(4y-3\right)\left(6t+1\right)$

Explanation of Solution

Given:

  $24ty-18t+4y-3$

Calculation:

The given polynomial is $24ty-18t+4y-3$

Make groups as shown below

  $\left(24ty-18t\right)+\left(4y-3\right)$

So, factored out the GCF from each of the group and then factored out the common factor

  $\begin{array}{l}\left(24ty-18t\right)+\left(4y-3\right)\\ =6t\left(4y-3\right)+1\left(4y-3\right)\\ =\left(4y-3\right)\left(6t+1\right)\end{array}$

So, the factored form is $\left(4y-3\right)\left(6t+1\right)$