Chapter 8.3, Problem 6MRE

To determine

To find : the value of $y$ when $x=2$

Answer to Problem 6MRE

The value of $y$ is $1$

Explanation of Solution

Given information : If $y=4$ when $x=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$

Calculation :

  $y$ Varies inversely as $x$ , then $xy=\text{constant}$

  $\begin{array}{l}{x}_2{y}_2=x_1{y}_1\\ y_2=\frac{x_1{y}_1}{x_2}\\ y=\frac{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.\times 4}{2}\\ y=\frac{2}{2}\\ y=1\end{array}$