Chapter 8.3, Problem 3MRE

To determine

To find : the value of $y$ when $x=\sqrt{6}$

Answer to Problem 3MRE

The value of $y$ is $3\sqrt{3}$

Explanation of Solution

Given information : If $y=3$ when $x=\sqrt{2}$

Calculation :

  $y$ Varies directly as $x$

  $\begin{array}{l}\frac{y_2}{x_2}=\frac{y_1}{x_1}\\ \frac{y}{\sqrt{6}}=\frac{3}{\sqrt{2}}\\ \sqrt{2}y=3\sqrt{6}\\ y=\frac{3\sqrt{6}}{\sqrt{2}}\\ y=3\sqrt{3}\end{array}$