Chapter 8.3, Problem 12OE

To determine

To find : the quotient and remainder of division

Answer to Problem 12OE

The quotient is $x$ and remainder is $2$

Explanation of Solution

Given information : $\frac{x^2-3x+2}{x-3}$

Calculation :

  $\frac{x^2-3x+2}{x-3}$

Separate into two fractions

Write as quotient $+\frac{remainder}{x}$

  $\begin{array}{l}\frac{x\left(x-3\right)+2}{x-3}\\ \frac{x\left(x-3\right)}{\left(x-3\right)}+\frac{2}{\left(x-3\right)}\\ x+\frac{2}{\left(x-3\right)}\end{array}$

So, the quotient is $x$ and the remainder is $2$