Smaller ion among K + and L i + has to be selected. Concept Introduction: Ionic radius is the distance between the atomic nucleus and outermost electron of an ion. Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii. Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns 1 .

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Answer 1

Question

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

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Answer 2

Question

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

Answer 6

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

Answer 7

Chapter 8.3, Problem 2PE

(a)

Interpretation Introduction

Interpretation: Smaller ion among K+ and Li+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 1A in the periodic table contains 1 valence electrons and the outer electronic configuration is ns1.

Answer 8

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

Answer 9

(b)

Interpretation Introduction

Interpretation: Smaller ion among Au+ and Au3+ has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

When an atom gets converted to a cation, the charge of nucleus remains the same while the number of electrons decreases. This decreases the repulsion and hence the electron cloud reduces which results in the decrease in ionic radius.

Answer 10

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

Answer 11

(c)

Interpretation Introduction

Interpretation: Smaller ion among P3− and N3− has to be selected.

Concept Introduction:

Ionic radius is the distance between the atomic nucleus and outermost electron of an ion.

Down the group, the principal quantum number increases and thus the size of orbital also increases which results in the increase in atomic radii.

Group 5A in the periodic table contains 5 valence electrons and the outer electronic configuration is ns2np3.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 8.2 - Practice Exercise An atom of a certain element has...Ch. 8.2 - Review of concepts Identify the elements whose...Ch. 8.3 - Practice Exercise Arrange the following atoms in...Ch. 8.3 - Prob. 1RC Ch. 8.3 - Prob. 2PE Ch. 8.3 - Prob. 2RC Ch. 8.4 - Prob. 1PE Ch. 8.4 - Prob. 1RC Ch. 8.5 - Prob. 1PE Ch. 8.5 - Prob. 1RC

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