The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.) 1. Is there a current induced through the wire of either of the loops: • before the switch is closed? Explain. • just after the switch is closed? Explain. • a long after the switch is closed? Explain. 2. For the period of time that there is a current included through the wire of the loops, find the direction of the current. 3. The ratio of the induced currents for the two loops is found by experiment to be equal to the inverse of the ratio of the resistances of the loops. What does this observation imply about the ratio of the induced emf in loop 1 to the induced emf in loop 2?

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 8.2, Problem 1aT

The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

Chapter 8.2, Problem 1aT, The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

1. Is there a current induced through the wire of either of the loops:

• before the switch is closed? Explain.
• just after the switch is closed? Explain.
• a long after the switch is closed? Explain.

2. For the period of time that there is a current included through the wire of the loops, find the direction of the current.
3. The ratio of the induced currents for the two loops is found by experiment to be equal to the inverse of the ratio of the resistances of the loops.

What does this observation imply about the ratio of the induced emf in loop 1 to the induced emf in loop 2?

(1)

Expert Solution

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

(2)

Expert Solution

To determine

To Find

The direction current induced through a wire of the loops.

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

(3)

Expert Solution

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

You are standing a distance x = 1.75 m away from this mirror. The object you are looking at is y = 0.29 m from the mirror. The angle of incidence is θ = 30°. What is the exact distance from you to the image?

For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you

A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).

Answer 2

Textbook Question

Chapter 8.2, Problem 1aT

The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

Chapter 8.2, Problem 1aT, The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

1. Is there a current induced through the wire of either of the loops:

• before the switch is closed? Explain.
• just after the switch is closed? Explain.
• a long after the switch is closed? Explain.

2. For the period of time that there is a current included through the wire of the loops, find the direction of the current.
3. The ratio of the induced currents for the two loops is found by experiment to be equal to the inverse of the ratio of the resistances of the loops.

What does this observation imply about the ratio of the induced emf in loop 1 to the induced emf in loop 2?

(1)

Expert Solution

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

(2)

Expert Solution

To determine

To Find

The direction current induced through a wire of the loops.

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

(3)

Expert Solution

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 8.2, Problem 1aT

The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

Chapter 8.2, Problem 1aT, The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

1. Is there a current induced through the wire of either of the loops:

• before the switch is closed? Explain.
• just after the switch is closed? Explain.
• a long after the switch is closed? Explain.

2. For the period of time that there is a current included through the wire of the loops, find the direction of the current.
3. The ratio of the induced currents for the two loops is found by experiment to be equal to the inverse of the ratio of the resistances of the loops.

What does this observation imply about the ratio of the induced emf in loop 1 to the induced emf in loop 2?

(1)

Expert Solution

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

(2)

Expert Solution

To determine

To Find

The direction current induced through a wire of the loops.

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

(3)

Expert Solution

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 8.2, Problem 1aT

The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

Chapter 8.2, Problem 1aT, The resistance of loop 2 is greater than that loop l. (The loop are made from different materials.)

1. Is there a current induced through the wire of either of the loops:

• before the switch is closed? Explain.
• just after the switch is closed? Explain.
• a long after the switch is closed? Explain.

2. For the period of time that there is a current included through the wire of the loops, find the direction of the current.
3. The ratio of the induced currents for the two loops is found by experiment to be equal to the inverse of the ratio of the resistances of the loops.

What does this observation imply about the ratio of the induced emf in loop 1 to the induced emf in loop 2?

(1)

Expert Solution

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

(2)

Expert Solution

To determine

To Find

The direction current induced through a wire of the loops.

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

(3)

Expert Solution

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(1)

Expert Solution

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

(2)

Expert Solution

To determine

To Find

The direction current induced through a wire of the loops.

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

(3)

Expert Solution

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.

Answer 8

(1)

Expert Solution

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

Answer 9

(1)

Expert Solution

Answer 10

(1)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

To Identify:

Induced current through wire of the loops as per the given conditions:

Before the switch is closed.
After when the switch is closed.
After a long-time when the switch is closed.

Answer 13

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux.

Case1: Before the switch is closed:

Before the switch is closed, there is no current flowing in solenoid (bigger loop) that can produce changing magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no induced current in small coils.

Case 2: After the switch gets closed:

Just after the switch is closed, the current in the solenoid (bigger loop) goes from zero to maximum which makes the magnetic field lines passing through the small loops change. Hence, due to change in flux, there will be induced current in them. The loop with higher resistance will be associated with less induced current.

Case 3: After longtimewhen the switch isclosed:

After long time the switch is closed, there is constant current in solenoid (bigger loop) that produces constant magnetic field. Hence, there is no change in flux in the small loops. Therefore, there is no current in small loops.

Conclusion:

Therefore, following Faraday’s law, there is an induced current in small coils just when switch is closed and is zero for other cases.

Answer 14

(2)

Expert Solution

To determine

To Find

The direction current induced through a wire of the loops.

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

Answer 15

(2)

Expert Solution

Answer 16

(2)

Expert Solution

Answer 17

Expert Solution

Answer 18

To determine

To Find

The direction current induced through a wire of the loops.

Answer 19

Explanation of Solution

Introduction:

According to Lenz’s law, the induced emf will form a magnetic field which counteracts the change in flux.

By seeing the sign of the battery (current flows from positive to negative terminal) and using the right-hand rule, the direction of magnetic field induced in the greater loop must be from left to right. When switch is closed, then the induced current in small loop is in such a way that decreases the magnetic flux produced by the larger loop, hence, the induced current is in clockwise while seeing the loop from right. When switch is opened, the induced current will flow in anticlockwise direction.

Conclusion:

Therefore, the current induced through a wire of the loop will be such that it will oppose the change in flux produced by the bigger loop.

Answer 20

(3)

Expert Solution

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.

Answer 21

(3)

Expert Solution

Answer 22

(3)

Expert Solution

Answer 23

Expert Solution

Answer 24

To determine

To Explain:

The ratio of induced emf in the loop 1to the loop 2.

Answer 25

Answer to Problem 1aT

Ratio of emf induced in loop 1to loop 2 is equal.

Answer 26

Explanation of Solution

Introduction:

According to Faradays’ law, an e.m.f is induced in a loop of wire if there is a rate of change in flux passing through the wire.

induced emf=−d∅dt

Where, ∅ is the flux which is the dot product of magnetic field and the area A of the loop.

∅=B→⋅A→

The induced emf depends on the rate of change in flux. Considering the area of the small loops same, the change in magnetic flux will be same for both the loops. Therefore, the induced emf will be same.

The induced current will be different in both the loops though, as the resistance of the loop 2 is greater than the loop 1.

Conclusion:

Therefore, induced emf will be same in both smaller loops.