Concept explainers
(a)
To Explain: the confidence interval
(a)
![Check Mark](/static/check-mark.png)
Explanation of Solution
Given:
95% confidence interval for the population proportion is given by (0.56, 0.62)
According to the given interval (0.56, 0.62) for 95% confidence interval, it means assuring 95% that proportion of U.S. adults who wish to lose weight so 95% of the proportion parameter will be lie between these two intervals and which is not come in these
(b)
To Explain: the point estimation and margin of error
(b)
![Check Mark](/static/check-mark.png)
Explanation of Solution
Given:
95% confidence interval for the population proportion is given by (0.56, 0.62)
Formula used:
Calculation:
Point estimation
It lies absolutely in the halfway of the confidence interval therefore the point estimate is then the average of the boundaries of the interval. Here point estimation of the interval of (0.56, 0.62) will be 0.59
Margin of error
Margin of error is half of the difference of confidence interval. Here margin of error of the interval of (0.63, 0.69) will be 0.03
(c)
To Explain: the claim on the basis of confidence interval
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 6E
Convincing evidence
Explanation of Solution
95% confidence interval for the population proportion is given by (0.56, 0.62) it means assuring 95% that proportion of U.S. adults who wish to lose weight. Observing that it is not likely that the population proportion who wants to lose weight is 0.50 so there is convincing evidence that more than half of the U.S. adults who want to lose weight.
Chapter 8 Solutions
PRACTICE OF STATISTICS F/AP EXAM
Additional Math Textbook Solutions
A First Course in Probability (10th Edition)
Thinking Mathematically (6th Edition)
Using and Understanding Mathematics: A Quantitative Reasoning Approach (6th Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Pre-Algebra Student Edition
College Algebra (7th Edition)
- At the same restaurant as in Question 19 with the same normal distribution, what's the chance of it taking no more than 15 minutes to get service?arrow_forwardClint, obviously not in college, sleeps an average of 8 hours per night with a standard deviation of 15 minutes. What's the chance of him sleeping between 7.5 and 8.5 hours on any given night? 0-(7-0) 200 91109s and doiw $20 (8-0) mol 8520 slang $199 galbrog seam side pide & D (newid se od poyesvig as PELEO PER AFTE editiw noudab temand van Czarrow_forwardTimes to complete a statistics exam have a normal distribution with a mean of 40 minutes and standard deviation of 6 minutes. Deshawn's time comes in at the 90th percentile. What percentage of the students are still working on their exams when Deshawn leaves?arrow_forward
- Suppose that the weights of cereal boxes have a normal distribution with a mean of 20 ounces and standard deviation of half an ounce. A box that has a standard score of o weighs how much? syed by ilog ni 21arrow_forwardBob scores 80 on both his math exam (which has a mean of 70 and standard deviation of 10) and his English exam (which has a mean of 85 and standard deviation of 5). Find and interpret Bob's Z-scores on both exams to let him know which exam (if either) he did bet- ter on. Don't, however, let his parents know; let them think he's just as good at both subjects. algas 70) sering digarrow_forwardSue's math class exam has a mean of 70 with a standard deviation of 5. Her standard score is-2. What's her original exam score?arrow_forward
- Clint sleeps an average of 8 hours per night with a standard deviation of 15 minutes. What's the chance he will sleep less than 7.5 hours tonight? nut bow visarrow_forwardSuppose that your score on an exam is directly at the mean. What's your standard score?arrow_forwardOne state's annual rainfall has a normal dis- tribution with a mean of 100 inches and standard deviation of 25 inches. Suppose that corn grows best when the annual rainfall is between 100 and 150 inches. What's the chance of achieving this amount of rainfall? wved now of sociarrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman
![Text book image](https://www.bartleby.com/isbn_cover_images/9781119256830/9781119256830_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305251809/9781305251809_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305504912/9781305504912_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134683416/9780134683416_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781319042578/9781319042578_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781319013387/9781319013387_smallCoverImage.gif)