EBK BIOLOGY
5th Edition
ISBN: 8220101337627
Author: Maier
Publisher: PEARSON
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Chapter 8, Problem 8LTB
Summary Introduction
Introduction:
DNA is a chain of the polynucleotide. A
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An individual with two different alleles at a locus is a(n)
Group of answer choices
A. clone
B. hemizygote
C. homozygote
D.heterozygote
Which of the following is a phenotype?
a. Aa
b. red hair
c. Heterozygous
d. DNA
Row
Select the row below that correctly identifies the genotype and phenotype of an individual who is heterozygous for the eye-colour allele.
Phenotype
Genotype
bb
Blue eyes
Blue eyes
A
B.
C
D.
Select one:
OA A
OB B
OC C
OD D
Bb
BB
Use the following information to answer the next question.
Bb
In humans, blue eyes (e) are encoded by an allele that is recessive to that
which encodes brown eyes (B).
Brown eyes
Brown eyes
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- Which of the following statements is most consistent with the results? А. В. C. D. Select one: O a. A is the child of B and C. O b. D is the child of B and C. O c.C is the child of A and B. O d. B is the child of A and C. ||||| | ||||| | ú | || ||| ||| | || | || | || <| || || || |||arrow_forwardA woman with type AB blood gave birth to a baby with type B blood. Two different men claim to be the father. One has type A blood, the other type B blood. Can the genetic evidence decide in favor of either? Will you be able to confidently decide on the identity of the father based solely on the data on blood type? Support your answer by showing your solutions and interpreting your data.arrow_forwardA researcher is interested in whether a disease gene is linked to an RFLP marker. A cross is made between pure breeding blind cavefish and pure breeding sighted cavefish. The lines are pure breeding. The resulting RFLP markers of the F1 offspring and the F2 (from an F1XF1 cross) offspring are shown. F1 F2 A. If the disease gene is 10 m.u. from the RFLP marker, what proportion of the F2 will have the gel pattern shown above AND be blind? Show your work B. If the disease gene is 10 mu. from the RFLP marker, what proportion of the F2 will have the gel pattern above AND NOT be blind? Show your work Blind cavefish Sighted cavefish Sighted cavefish 1 Sighted cavefisharrow_forward
- When people move to hot climates, their bodies increase sweat production to manage the heat-induced body stress. This increase in sweat production is associated with an allele change within the individuals genome. a. True b. Falsearrow_forwardUse the picture below to answer the questions that follow. A ∞ SE Which of letters indicate: 1) identical molecules of DNA [Select] B 2) similar molecules of DNA, can have different alleles [Select] 3) the result of S phase [Select] 4) Do the two chromosomes (red and blue) have the same genes? [Select]arrow_forwardis a segment of DNA whose sequence of nucleotides codes for a 7. A protein. a. gene b. chromosome c. karyotype d. characteristic 8. A Is a graphic display of chromosomes, arranged by size and shape. a. genotype b. phenotype C. monotype d. karyotype 9. In purple people eaters, one-horn is dominant and no horns is recessive. Draw a Punnett Square showing the cross of a purple people eater that is heterozygous for horns with a purple people eater that does not have horns. Summarize the genotypes & phenotypes of the possible offspring. 10. Blood typing: a. The father of a child has type AB blood. The mother has type A. Which blood types can their children NOT have? b. A woman with type A blood and a man with type B blood could potentially have offspring with what blood types? c. The mother has type A blood. Her husband has type B blood. Their child has type O blood. The father claims the child can't be his. Is he right?arrow_forward
- Which of the following is a homozygous representation? O a. Bb O b. Aa O C. xHxh Od.aaarrow_forwardIf a woman who is a carrier for Tay-Sachs has children with a man who is not a Tay-Sachs carrier, what is the probability that one of their children will be a carrier for Tay-Sachs? (Sketch a Punnett square to help you find the correct answer.) a. None b. 25% c. 50% d. 75% e. 100%arrow_forwardA mother who is blood type a B has a child who is a B also. A potential father‘s blood type O. A geneticist concludes that. A. He cannot be the father B. He is very likely to be the father C. No conclusion can be drawnarrow_forward
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