Chapter 8, Problem 8C.6E

(a)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction between cesium and oxygen has to be written.

Answer to Problem 8C.6E

The chemical equation for the reaction between cesium and oxygen is,

  ${\text{4Cs}}_{\left(\text{s}\right)}{\text{+O}}_{\text{2(g)}}\stackrel{}{\to }{\text{2Cs}}_{\text{2}}{\text{O}}_{\text{(s)}}$

Explanation of Solution

Cesium reacts with oxygen to form cesium oxide.  The chemical equation for the reaction between cesium and oxygen is,

  ${\text{Cs}}_{\left(\text{s}\right)}{\text{+O}}_{\text{2(g)}}\stackrel{}{\to }{\text{Cs}}_{\text{2}}{\text{O}}_{\text{(s)}}$

Four moles of cesium are required in the reactant side and two moles of cesium oxide are required in the product side to make the equation a balanced one.  The balanced chemical equation for the reaction between cesium and oxygen is,

  ${\text{4Cs}}_{\left(\text{s}\right)}{\text{+O}}_{\text{2(g)}}\stackrel{}{\to }{\text{2Cs}}_{\text{2}}{\text{O}}_{\text{(s)}}$

(b)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction between sodium oxide and water has to be written.

Answer to Problem 8C.6E

The chemical equation for the reaction between sodium oxide and water is,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{2NaOH}}_{\left(\text{aq}\right)}$

Explanation of Solution

Sodium oxide reacts with water to form sodium hydroxide.  The chemical equation is written as,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{NaOH}}_{\left(\text{aq}\right)}$

Two moles of sodium hydroxide are required in the product side to make the equation a balanced one.  The balanced chemical equation for the reaction between sodium oxide and water is,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{2NaOH}}_{\left(\text{aq}\right)}$

(c)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction between lithium and hydrochloric acid has to be written.

Answer to Problem 8C.6E

The chemical equation for the reaction between lithium and hydrochloric acid is,

  ${\text{2Li}}_{\left(\text{s}\right)}{\text{+2HCl}}_{\left(\text{aq}\right)}\stackrel{}{\to }{\text{2LiCl}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2(g)}}$

Explanation of Solution

Lithium reacts with hydrochloric acid to form lithium chloride with the evolution of hydrogen gas.  The chemical reaction is,

  ${\text{Li}}_{\left(\text{s}\right)}{\text{+HCl}}_{\left(\text{aq}\right)}\stackrel{}{\to }{\text{LiCl}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2(g)}}$

Two moles of lithium and two moles of hydrochloric acid are required in the reactant side, and two moles of lithium chloride are required in the product side to make the equation a balanced one.  The balanced chemical equation for the reaction between lithium and hydrochloric acid is,

  ${\text{2Li}}_{\left(\text{s}\right)}{\text{+2HCl}}_{\left(\text{aq}\right)}\stackrel{}{\to }{\text{2LiCl}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2(g)}}$

(d)

Interpretation Introduction

Interpretation:

The chemical equation for the reaction between cesium and iodine has to be written.

Answer to Problem 8C.6E

The chemical equation for the reaction between cesium and iodine is,

  ${\text{2Cs}}_{\left(\text{s}\right)}{\text{+I}}_{\text{2(g)}}\stackrel{}{\to }{\text{2CsI}}_{\left(\text{s}\right)}$

Explanation of Solution

Cesium reacts with iodine to form cesium iodide.  The chemical reaction is,

  ${\text{Cs}}_{\left(\text{s}\right)}{\text{+I}}_{\text{2(g)}}\stackrel{}{\to }{\text{CsI}}_{\left(\text{s}\right)}$

Two moles of cesium are required in the reactant side and two moles of cesium iodide are required in the product side to make the equation a balanced one.  The balanced chemical equation for the reaction between cesium and iodine is,

  ${\text{2Cs}}_{\left(\text{s}\right)}{\text{+I}}_{\text{2(g)}}\stackrel{}{\to }{\text{2CsI}}_{\left(\text{s}\right)}$