EBK MODERN DATABASE MANAGEMENT,
13th Edition
ISBN: 9780134792279
Author: TOPI
Publisher: YUZU
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Chapter 8, Problem 8.54PAE
Program Plan Intro
Problems that might arise from vertical partitioning of a relation and general conditions influencing them.
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Given these potential problems, what general conditions influence when to partition a relation vertically?
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Chapter 8 Solutions
EBK MODERN DATABASE MANAGEMENT,
Ch. 8 - Prob. 8.1RQCh. 8 - Prob. 8.2RQCh. 8 - Prob. 8.3RQCh. 8 - Prob. 8.4RQCh. 8 - Prob. 8.5RQCh. 8 - Prob. 8.6RQCh. 8 - Prob. 8.7RQCh. 8 - Prob. 8.8RQCh. 8 - Explain why you sometimes have to reserve much...Ch. 8 - Why are field values sometimes coded?
Ch. 8 - Prob. 8.11RQCh. 8 - Prob. 8.12RQCh. 8 - Explain why normalized relations may not comprise...Ch. 8 - Prob. 8.14RQCh. 8 - List three common situations that suggest that...Ch. 8 - Explain the reasons why some experts are against...Ch. 8 - Prob. 8.17RQCh. 8 - Prob. 8.18RQCh. 8 - Prob. 8.19RQCh. 8 - Prob. 8.20RQCh. 8 - Prob. 8.21RQCh. 8 - Prob. 8.22RQCh. 8 - One of the strongest recommendations regarding...Ch. 8 - Explain why an index is useful only if there is...Ch. 8 - Indexing can clearly be very beneficial. Why...Ch. 8 - Prob. 8.26RQCh. 8 - Prob. 8.27RQCh. 8 - Describe the role of data dictionary in the...Ch. 8 - Prob. 8.29RQCh. 8 - Prob. 8.30RQCh. 8 - Explain how creating a view may increase data...Ch. 8 - Prob. 8.32RQCh. 8 - Prob. 8.33RQCh. 8 - Prob. 8.34RQCh. 8 - Prob. 8.35RQCh. 8 - Prob. 8.36RQCh. 8 - Prob. 8.37RQCh. 8 - Prob. 8.38RQCh. 8 - Prob. 8.39RQCh. 8 - How can views be used as part of data security?...Ch. 8 - Prob. 8.41RQCh. 8 - Prob. 8.42RQCh. 8 - Consider the following two relations for...Ch. 8 - Prob. 8.44PAECh. 8 - Prob. 8.45PAECh. 8 - Prob. 8.46PAECh. 8 - Prob. 8.47PAECh. 8 - Suppose you are designing a default value for the...Ch. 8 - When a student has not chosen a major at a...Ch. 8 - Prob. 8.50PAECh. 8 - Prob. 8.51PAECh. 8 - Consider the relations in Problem and Exercise...Ch. 8 - Prob. 8.53PAECh. 8 - Prob. 8.54PAECh. 8 - Prob. 8.55PAECh. 8 - Prob. 8.56PAECh. 8 - Prob. 8.57PAECh. 8 - Consider the relations specified in Problem and...Ch. 8 - Prob. 8.59PAECh. 8 - Prob. 8.60PAECh. 8 - Prob. 8.61PAECh. 8 - Prob. 8.62PAECh. 8 - Prob. 8.63PAECh. 8 - Prob. 8.64PAECh. 8 - Problems and Exercises 8-65 through 8-68 refer to...Ch. 8 - Prob. 8.66PAECh. 8 - Problems and Exercises 8-65i5 through 8-68 refer...Ch. 8 - Refer to Figure 4-5 0. For each of the following...Ch. 8 - Prob. 8.69PAECh. 8 - Prob. 8.70PAECh. 8 - Prob. 8.71PAECh. 8 - Prob. 8.72PAECh. 8 - Prob. 8.73PAECh. 8 - Prob. 8.74PAECh. 8 - Prob. 8.75PAECh. 8 - Prob. 8.76PAECh. 8 - Prob. 8.77PAE
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- How does the primary key of a relation relate to the interdependencies among its other attributes from a practical standpoint?arrow_forwardHow does the primary key of a relation relate to the interdependencies of its characteristics from a functional standpoint?arrow_forwardAn explanation of the three circumstances in which the secondary key of a relation should be used instead of the main key of the connectionarrow_forward
- Explain three scenarios in which a surrogate key for a relation's primary key should be generated.arrow_forwardWhat are the conditions under which an attribute of a relation may have a changeable length?arrow_forwardMCQS In RDBMS, each attribute is represented only even for foreign keys true false To convert a DBMS into 1 NF, we remove all the functional dependencies from the relation true false A relation can have maximum number of attributes necessary to support the data requirements of the enterprise true false Joins in RDBMS relations are always loss-less true false To cater for various types of anomalies, we can break the relation into two with a foreign key to reference the parent relation True False RDBMS are optimized for storage True Falsearrow_forward
- Describe three circumstances in which a substitute key for a relation's primary key should be established.arrow_forwardWhat are three advantages of using a surrogate key rather than the main key to access a relation instead?arrow_forwardexplanation of three situations in which a relation's secondary key should be set in place of the primary keyarrow_forward
- Here are three examples of when it makes sense to create a surrogate key in place of the primary key in a relation.arrow_forwardBased on the following functional dependencies, for the relation SCHEDULE bring it into a set of 3NF relations. Dependencies: Section#, CourseID, Semester ID → RoomNo Section#, CourseID, Semester ID → Inst_ID Section#, CourseID, Semester ID → Week_day Section#, CourseID, Semester ID → Start_time Section#, CourseID, Semester ID → End_time Course_ID → Course Name RoomNo → Occupancy Instr_ID → Instr_name SCHEDULE CourseID, Section#, Semester ID, Course Name ,RoomNo, Occupancy, Inst_ID, Instr_Name, Week_day, Start_time, End_time)arrow_forwardWhat does it mean to be related? How do you define a relation's properties?arrow_forward
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