Chapter 8, Problem 8.36QP

Interpretation Introduction

Interpretation: To calculate the production of quicklime $\left(\text{CaO}\right)$ in grams from decomposition of $\text{1}\text{.0}\text{Kg}$ of limestone $\left({\text{CaCO}}_{\text{3}}\right)$

Concept introduction:

Balanced chemical equation: The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass.

 $\begin{array}{l}\text{Mass}\text{of}\text{starting}\text{materials}\left(\text{Reactants}\right)\text{=}\text{Mass}\text{of}\text{products}\\ {\text{N}}_{\text{2}}\text{+}{\text{H}}_{\text{2}}\to {\text{NH}}_{\text{3}}\end{array}$

In the above reaction 2 nitrogen atoms are there in reactant side but 1 nitrogen in product side, likewise 2 hydrogen’s in reactant side but 3 hydrogen’s in product side so this is unbalanced equation by putting coefficients for each elements in both sides we can balance this reaction as follows:

${\text{N}}_{\text{2}}\text{+}{\text{3H}}_{\text{2}}\to {\text{2NH}}_{\text{3}}$

To calculate: The production of quicklime from decomposition of $\text{1}\text{.0}\text{Kg}$ of limestone.