The more reactive compound should be identified from the given pair compounds for an E2 reaction. Concept introduction: In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide. E2 reaction is a bimolecular elimination reaction in which only one step is involved and both the substrate and base are depending upon the rate of reaction . The reactivity of substrates are depends upon the transition state and the stability of formed alkene product . The more substituted alkenes are more stable as compared to less substituted alkenes . The more alkyl group attachment to a double bond make it more stable due to the + I effect of alkyl groups. It means the alkyl groups will push electrons towards the double bonded carbon atoms, so the double bond becomes strengthened and highly stabilized . To identify: the more reactive compound in E2 reaction from the pair of given compounds.

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 73PP

(a)

Interpretation Introduction

Interpretation:

The more reactive compound should be identified from the given pair compounds for an E2 reaction.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

E2 reaction is a bimolecular elimination reaction in which only one step is involved and both the substrate and base are depending upon the rate of reaction.

The reactivity of substrates are depends upon the transition state and the stability of formed alkene product.

The more substituted alkenes are more stable as compared to less substituted alkenes. The more alkyl group attachment to a double bond make it more stable due to the ⁺I effect of alkyl groups. It means the alkyl groups will push electrons towards the double bonded carbon atoms, so the double bond becomes strengthened and highly stabilized.

To identify: the more reactive compound in E2 reaction from the pair of given compounds.

(b)

Interpretation Introduction

Interpretation:

The more reactive compound should be identified from the given pair compounds for an E2 reaction.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.

E2 reaction is a bimolecular elimination reaction in which only one step is involved and both the substrate and base are depending upon the rate of reaction.

The reactivity of substrates are depends upon the transition state and the stability of formed alkene product.

The more substituted alkenes are more stable as compared to less substituted alkenes. The more alkyl group attachment to a double bond make it more stable due to the ⁺I effect of alkyl groups. It means the alkyl groups will push electrons towards the double bonded carbon atoms, so the double bond becomes strengthened and highly stabilized.

To identify: the more reactive compound in E2 reaction from the pair of given compounds.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Predict the major organic product(s) of the following reactions. Indicate which of the following mechanisms is in operation: SN1, SN2, E1, or E2.

(c) (4pts) Mechanism: heat (E1) CH3OH + 1.5pts each _E1 _ (1pt) Br CH3OH (d) (4pts) Mechanism: SN1 (1pt) (e) (3pts) 1111 I H 10 Ill!! H LDA THF (solvent) Mechanism: E2 (1pt) NC (f) Bri!!!!! CH3 NaCN (3pts) acetone Mechanism: SN2 (1pt) (SN1) -OCH3 OCH3 1.5pts each 2pts for either product 1pt if incorrect stereochemistry H Br (g) “,、 (3pts) H CH3OH +21 Mechanism: SN2 (1pt) H CH3 2pts 1pt if incorrect stereochemistry H 2pts 1pt if incorrect stereochemistry

A mixture of butyl acrylate and 4'-chloropropiophenone has been taken for proton NMR analysis. Based on this proton NMR, determine the relative percentage of each compound in the mixture