(a) Interpretation: 80 μg/kg of chloroform is to be converted into parts per million. Concept introduction: The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 10 6 parts of solution. Mathematically, the concentration in parts per million is expressed as follows: parts per million ( ppm ) = Mass of solute ( g ) Mass of solution ( g ) × 10 6 In terms of volume, the parts per million may be expressed as follows: parts per million ( ppm ) = Volume of solute ( mL ) Volume of solution ( mL ) × 10 6 The conversion factor to convert micrograms to kilograms is as follows: 1 μg = 10 − 9 kg The conversion factor to convert kilograms to grams is as follows: 1 kg = 10 3 g

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NO(g) +Cl₂ (g) = 2NOC1 (g) AGº = -41. kJ Now suppose a reaction vessel is filled with 8.90 atm of chlorine (C12) and 5.71 atm of nitrosyl chloride (NOC1) at 1075. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. atm ☑ 18 Ar

Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCN is a weak acid. acids: 0.29 mol of NaOH is added to 1.0 L of a 1.2M HCN solution. bases: ☑ other: 0.09 mol of HCl is added to acids: 1.0 L of a solution that is bases: 0.3M in both HCN and KCN. other: 0,0,... ? 00. 18 Ar 日

Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 0.2 mol of KOH is added to 1.0 L of a 0.5 M HF solution. bases: Х other: ☐ acids: 0.10 mol of HI is added to 1.0 L of a solution that is 1.4M in both HF and NaF. bases: other: ☐ 0,0,... ด ? 18 Ar

Answer 2

Question

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Answer 6

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Answer 7

Chapter 8, Problem 67P

Interpretation Introduction

(a)

Interpretation:

80 μg/kg of chloroform is to be converted into parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Answer 8

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Answer 9

Interpretation Introduction

(b)

Interpretation:

700 μg/kg of glyphosate present in water is to be converted to parts per million.

Concept introduction:

The concentration units are preferentially expressed in parts per million in cases where the solute is present in very minor amount. Analogous to the percentage concentration parts per million is defined as number of parts of solute present in 106 parts of solution. Mathematically, the concentration in parts per million is expressed as follows:

parts per million(ppm)=Mass of solute(g)Mass of solution(g)×106

In terms of volume, the parts per million may be expressed as follows:

parts per million(ppm)= Volume of solute(mL) Volume of solution(mL)×106

The conversion factor to convert micrograms to kilograms is as follows:

1 μg=10−9 kg

The conversion factor to convert kilograms to grams is as follows:

1 kg=103 g

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 8.1 - Classify each substance as a heterogeneous...Ch. 8.1 - Use the appearance of each product to classify it...Ch. 8.2 - Consider the following diagrams for an aqueous...Ch. 8.2 - Classify each solution as an electrolyte or...Ch. 8.2 - Using the given number of moles, determine how...Ch. 8.2 - Prob. 8.2PP Ch. 8.2 - A solution contains the following ions:...Ch. 8.2 - If a solution contains 125 mEq of Na+ per liter,...Ch. 8.3 - Which compounds are water soluble? a. NaNO3 b. CH4...Ch. 8.3 - Prob. 8.7P

Want to see the full answer?

Chapter 8 Solutions