The oxidation number of carbon in CO should be determined. Concept Introduction: For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound. For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O 3 , O 2 , S 8 , aluminum metal, P 4 all have 0 oxidation number. The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl - . Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O 3 , O 2 , O 2 2 - , and H 2 O 2 .

Question

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Answer 1

Question

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

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Answer 2

Question

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

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Answer 3

Question

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

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Answer 4

Question

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

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Answer 5

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 6

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 7

Chapter 8, Problem 55AP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CO should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The oxidation state of carbon in CO₂ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₄ should be determined.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 12

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 13

(d)

Interpretation Introduction

Interpretation:

The oxidation number of carbon inCCl₄ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 14

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

Answer 15

(e)

Interpretation Introduction

Interpretation:

The oxidation number of carbon in CH₂F₂ should be calculated.

Concept Introduction:

For any atom, the oxidation number is the number of charges present on the atoms. It plays an important role in the systematic nomenclature of chemical compound.

For any atom, oxidation number would be zero then it is a neutral element and it comprises atoms of only single element. Therefore, the atoms present in O₃, O₂, S₈, aluminum metal, P₄ all have 0 oxidation number.

The oxidation state of an ion is simply the charge exist on it. For example, the oxidation state of sodium in Na+ is +1 and similarly -1 for chlorine in Cl^-.

Oxygen usually have -2 oxidation number. But there are some exceptions for polyatomic ions which has O-O bonds like O₃, O₂, O₂²^-, and H₂O₂.

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