What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained. Concept Introduction: One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction. Here, Oxidation is loss of electrons. Reduction is gain of electrons. For example, the reaction of magnesium with chlorine shown below: Mg ( s ) + 2 HCl ( g ) → MgCl 2 ( aq ) + H 2 ( g ) Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl 2 is 2+, thus, oxidation of Mg to Mg 2 + results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H 2 is zero, reduction of hydrogen from HCl to H 2 results in decrease in oxidation state.

Question

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Answer 1

Question

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.

Conclusion

Thus, oxidation number is increased during oxidation and it is decreased during reduction.

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Answer 2

Question

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.

Conclusion

Thus, oxidation number is increased during oxidation and it is decreased during reduction.

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Answer 3

Question

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.

Conclusion

Thus, oxidation number is increased during oxidation and it is decreased during reduction.

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Answer 4

Question

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.

Conclusion

Thus, oxidation number is increased during oxidation and it is decreased during reduction.

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Answer 5

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.

Conclusion

Thus, oxidation number is increased during oxidation and it is decreased during reduction.

Answer 6

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.

Conclusion

Thus, oxidation number is increased during oxidation and it is decreased during reduction.

Answer 7

Chapter 8, Problem 1RQ

Interpretation Introduction

Interpretation:

What happens to the oxidation number of one of its elements when a compound is oxidized and when it is reduced, must be explained.

Concept Introduction:

One of the ways to define oxidation and reduction involves gain or loss of electrons by elements during the reaction.

Here,

Oxidation is loss of electrons.

Reduction is gain of electrons.

For example, the reaction of magnesium with chlorine shown below:

Mg(s)+2HCl(g)→MgCl2(aq)+H2(g)

Here, the oxidation state of magnesium in Mg(s) is zero and that in MgCl₂ is 2+, thus, oxidation of Mg to Mg²+ results in increase in oxidation state. Similarly, the oxidation state of hydrogen in HCl is +1 and that in H₂ is zero, reduction of hydrogen from HCl to H₂ results in decrease in oxidation state.

Answer 8

Expert Solution & Answer

Answer to Problem 1RQ

Solution:

Oxidation number of one of its elements is increased when a compound is oxidized.

Oxidation number of one of its elements is decreased when a compound is reduced.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Oxidation number is defined as the charge present on a simple ion or atom.

In any reaction, reduction results due to gain of electron, if an atom or ion gain electrons it gets negative charge, or its negative charge increases. Thus, oxidation state of that atom decreases. Similarly, oxidation results due to loss of electron, if an atom or ion lose electrons it gets positive charge, or its positive charge increases.