EBK CHEMISTRY FOR CHANGING TIMES
EBK CHEMISTRY FOR CHANGING TIMES
14th Edition
ISBN: 8220100663482
Author: MCCREARY
Publisher: PEARSON
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Chapter 8, Problem 52P

a)

Interpretation Introduction

Interpretation - Here we are asked to write the formula(s) for the product(s) formed when the following substances S reacts with oxygen (O2).

Concept Introduction - Combustion is an exothermic redox reaction between the reductant (fuel) and the oxidant (usually oxygen) and this produces oxidized products. Combustion is a complicated chain of reaction. The reductant first undergo endothermic pyrolysis to form gaseous products whose burning then provides the heat needed to produce more of them. During complete combustion, the reactants burns completely in presence of oxygen and generates a limited number of products. When the elements undergo combustion, the products are mostly the common oxides.

b)

Interpretation Introduction

Interpretation - Here we are asked to write the formula(s) for the product(s) formed when the following substances CH3OH reacts with oxygen (O2).

Concept Introduction - Combustion is an exothermic redox reaction between the reductant (fuel) and the oxidant (usually oxygen) and this produces oxidized products. Combustion is a complicated chain of reaction. The resultant first undergo endothermic pyrolysis to form gaseous products whose burning then provides the heat needed to produce more of them. During complete combustion, the reactants burns completely in presence of oxygen and generates a limited number of products. When the elements undergo combustion, the products are mostly the common oxides.

Solution - 2 molecules of Carbon dioxide and 4 molecules of water

Explanation −

Methanol (CH3OH) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). The chemical reaction is given below:

    EBK CHEMISTRY FOR CHANGING TIMES, Chapter 8, Problem 52P , additional homework tip  1

c)

Interpretation - Here we are asked to write the formula(s) for the product(s) formed when the following substances C3H6O reacts with oxygen (O2).

Concept Introduction - Combustion is an exothermic redox reaction between the reductant (fuel) and the oxidant (usually oxygen) and this produces oxidized products. Combustion is a complicated chain of reaction. The resultant first undergo endothermic pyrolysis to form gaseous products whose burning then provides the heat needed to produce more of them. During complete combustion, the reactants burns completely in presence of oxygen and generates a limited number of products. When the elements undergo combustion, the products are mostly the common oxides.

Solution- 6 molecules of Carbon dioxide and water

Explanation -The compound (C3H6O) reacts with oxygen (O2) to form a carbon dioxide (CO2) and water (H2O). The chemical reaction is given below:

    EBK CHEMISTRY FOR CHANGING TIMES, Chapter 8, Problem 52P , additional homework tip  2

Conclusion - The energy produced by combustion is harvested for diverse uses like electricity generation, cooking etc.

c)

Interpretation Introduction

Interpretation - Here we are asked to write the formula(s) for the product(s) formed when the following substances C3H6O reacts with oxygen (O2).

Concept Introduction - Combustion is an exothermic redox reaction between the reductant (fuel) and the oxidant (usually oxygen) and this produces oxidized products. Combustion is a complicated chain of reaction. The resultant first undergo endothermic pyrolysis to form gaseous products whose burning then provides the heat needed to produce more of them. During complete combustion, the reactants burns completely in presence of oxygen and generates a limited number of products. When the elements undergo combustion, the products are mostly the common oxides.

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Chapter 8 Solutions

EBK CHEMISTRY FOR CHANGING TIMES

Ch. 8 - Prob. 11RQCh. 8 - Prob. 12RQCh. 8 - Prob. 13RQCh. 8 - Prob. 14RQCh. 8 - Prob. 15RQCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - 20. Write a balanced reduction half-reaction...Ch. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Prob. 39PCh. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - Prob. 42PCh. 8 - Prob. 43PCh. 8 - 44. Tantalum, a metal used m electronic devices...Ch. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - Prob. 48PCh. 8 - Prob. 49PCh. 8 - Prob. 50PCh. 8 - Prob. 51PCh. 8 - Prob. 52PCh. 8 - Prob. 53PCh. 8 - Prob. 54PCh. 8 - Prob. 55APCh. 8 - Prob. 56APCh. 8 - Prob. 57APCh. 8 - Prob. 58APCh. 8 - Prob. 59APCh. 8 - Prob. 60APCh. 8 - Prob. 61APCh. 8 - When exposed to air containing hydrogen sulfide,...Ch. 8 - Prob. 63APCh. 8 - Prob. 64APCh. 8 - Prob. 65APCh. 8 - Prob. 66APCh. 8 - Prob. 67APCh. 8 - Prob. 68APCh. 8 - Prob. 69APCh. 8 - Prob. 70APCh. 8 - Prob. 71APCh. 8 - Prob. 72APCh. 8 - Prob. 73APCh. 8 - Prob. 74APCh. 8 - Prob. 75APCh. 8 - Prob. 76APCh. 8 - Prob. 77APCh. 8 - Prob. 78APCh. 8 - Prob. 79APCh. 8 - Prob. 80APCh. 8 - Prob. 8.1CTECh. 8 - Prob. 8.2CTECh. 8 - Prob. 8.3CTECh. 8 - Prob. 8.4CTECh. 8 - Prob. 8.5CTECh. 8 - Prob. 8.6CTECh. 8 - Prob. 8.7CTECh. 8 - Prob. 1CGPCh. 8 - Prob. 2CGPCh. 8 - Prob. 3CGPCh. 8 - Prob. 4CGPCh. 8 - Prob. 5CGPCh. 8 - Prob. 1CHQCh. 8 - Prob. 2CHQCh. 8 - Prob. 3CHQCh. 8 - Prob. 4CHQCh. 8 - Prob. 5CHQ
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