For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at 24°C . Concept introduction: By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law . According to ideal gas law, PV=nRT Where, P = pressure in atmospheres V= volumes in liters n = number of moles R =universal gas constant ( 0.08206 L ⋅ a t m / K ⋅ m o l ) T = temperature in kelvins By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation. The mass of a given substance can be calculated by, M a s s i n g r a m = n u m b e r o f m o l e s × g r a m m o l e c u l a r m a s s

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Chapter 8, Problem 49E

Interpretation Introduction

Interpretation: For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at 24°C .

Concept introduction:

By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law.

According to ideal gas law,

                                            PV=nRT

Where,

          P = pressure in atmospheres

          V= volumes in liters

          n = number of moles

          R =universal gas constant ( 0.08206L⋅atm/K⋅mol )

          T = temperature in kelvins

By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation.

The mass of a given substance can be calculated by,

               Mass in gram = number of moles ×gram molecular mass

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