Explanation a) Alpha decay of Rn − 220 In a nuclear equation, each element is represented by its appropriate chemical symbol. There are two numbers written along with the chemical symbol. One is the mass number, which is written on the upper side and the other is the atomic number, which is written on the lower side. The mass number is denoted by A and the atomic number is denoted by Z. In a balanced nuclear equation, the sum of atomic number and mass number is the same on both sides of the nuclear equation. The balanced nuclear equation for the alpha decay of Rn − 220 is represented as follows: 86 220 Rn → 84 216 Po + 2 4 He In this equation, the sum of atomic numbers is the same on both sides, that is, 86 and the sum of mass numbers is also the same on both sides, that is, 220 . b) Beta decay of Bi − 212 In a balanced nuclear equation, the sum of mass number and atomic number is the same on both sides of the equation. The balanced nuclear equation for the beta decay of Bi − 212 is represented as follows: 83 212 Bi → 84 212 Po + − 1 0 e In this equation, the sum of atomic numbers is the same on both sides, that is, 83 and the sum of mass numbers is also the same on both sides, that is, 212

6th Edition

ISBN: 9781305084476

Author: Tro, Nivaldo J., Neu, Don.

Publisher: Cengage Learning

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Concept explainers

Writing and Balancing Nuclear Equations

A nuclear equation is a symbolic representation of a nuclear reaction using certain symbols. It is studied in nuclear chemistry and nuclear physics.

Question

Chapter 8, Problem 32E

Interpretation Introduction

Interpretation:

The balanced nuclear equation for each of the given processes is to be represented.

Concept Introduction:

There is a difference between a chemical reaction and a nuclear reaction. A chemical reaction involves atoms, molecules and electrons whereas a nuclear reaction involves the nucleus of an atom.

Expert Solution & Answer

Chapter 8 Solutions

Chemistry In Focus

Ch. 8 - Prob. 8.1YT Ch. 8 - Prob. 8.2YT Ch. 8 - Prob. 8.3YT Ch. 8 - Prob. 8.4YT Ch. 8 - Prob. 8.5YT Ch. 8 - Prob. 1SC Ch. 8 - Prob. 2SC Ch. 8 - Prob. 3SC Ch. 8 - Prob. 4SC Ch. 8 - Prob. 5SC

Ch. 8 - Prob. 6SC Ch. 8 - Prob. 7SC Ch. 8 - Prob. 1E Ch. 8 - Prob. 2E Ch. 8 - Prob. 3E Ch. 8 - Prob. 4E Ch. 8 - Prob. 5E Ch. 8 - Prob. 6E Ch. 8 - Prob. 7E Ch. 8 - Prob. 8E Ch. 8 - Prob. 9E Ch. 8 - Prob. 10E Ch. 8 - Prob. 11E Ch. 8 - Prob. 12E Ch. 8 - Prob. 13E Ch. 8 - Prob. 14E Ch. 8 - Prob. 15E Ch. 8 - Prob. 16E Ch. 8 - Prob. 17E Ch. 8 - Prob. 18E Ch. 8 - Prob. 19E Ch. 8 - Prob. 20E Ch. 8 - Prob. 21E Ch. 8 - Prob. 22E Ch. 8 - Prob. 23E Ch. 8 - Prob. 24E Ch. 8 - Prob. 25E Ch. 8 - Prob. 26E Ch. 8 - Prob. 27E Ch. 8 - Prob. 28E Ch. 8 - Prob. 29E Ch. 8 - Prob. 30E Ch. 8 - Prob. 31E Ch. 8 - Prob. 32E Ch. 8 - Prob. 33E Ch. 8 - Prob. 34E Ch. 8 - Prob. 35E Ch. 8 - Prob. 36E Ch. 8 - Prob. 37E Ch. 8 - Prob. 38E Ch. 8 - Prob. 39E Ch. 8 - Prob. 40E Ch. 8 - Prob. 42E Ch. 8 - Prob. 43E Ch. 8 - Prob. 44E Ch. 8 - Prob. 45E Ch. 8 - Prob. 46E Ch. 8 - Prob. 47E Ch. 8 - Prob. 48E Ch. 8 - Prob. 49E Ch. 8 - Prob. 50E Ch. 8 - Prob. 51E Ch. 8 - Prob. 52E Ch. 8 - Prob. 53E Ch. 8 - Prob. 54E Ch. 8 - Prob. 55E Ch. 8 - Prob. 56E Ch. 8 - Prob. 57E Ch. 8 - Prob. 58E Ch. 8 - Prob. 59E Ch. 8 - Prob. 62E Ch. 8 - Prob. 63E Ch. 8 - Prob. 64E Ch. 8 - Prob. 65E Ch. 8 - Prob. 66E Ch. 8 - Prob. 67E Ch. 8 - Prob. 68E Ch. 8 - Prob. 69E Ch. 8 - Prob. 70E

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Francium was discovered as a minor decay product of actinium-227. Write the nuclear equation for the decay of actinium-227 by alpha emission.

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